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3 years ago

Satellite communication is only possible using

Physics

2 answers:

RoseWind [281]3 years ago

8 0

Answer:

its b

Explanation:

Maurinko [17]3 years ago

5 0

Answer:

B) digital transmition

Explanation:

using radio waves to transmit the information.

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State three ways in which a machines are useful to us.

olga2289 [7]

1: a machine makes our work easier

2: a machine can help us find important information

3: a machine can help us transport from a place to another

3 0

3 years ago

A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1

Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) $I=0.0085\ A$

Explanation:

Given:

radius if the coil, $r=0.0395\ m$

no. of turns in the coil, $n=520$

variation of the magnetic field in the coil, $B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4$

resistor connected to the coil, $R=560\ \Omega$

(a)

we know, according to Faraday's Law:

$emf=n.\frac{d\phi}{dt}$

where:

$d \phi=$ change in associated magnetic flux

$\phi= B.A$

where:

A= area enclosed by the coil

Here

$A=\pi.r^2$

$A=\pi\times 0.0395^2$

$A=0.0049\ m^2$

$\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049$

So, emf:

$emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]$

$emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]$

$emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]$

$emf= 0.0306+3.516\times 10^{-4}\ t^3$

(b)

Given:

$t_0=5.25\ s$

Now, emf at given time:

$emf=4.7755\times 10^{-2}\ V$

∴Current

$I=\frac{emf}{R}$

$I=\frac{4.7755\times 10^{-2}}{560}$

$I=8.5\times 10^{-5} A$

6 0

4 years ago

(02.03 LC)

guapka [62]

Ina vacuum, it is a constant value that does not depend on the observer.

8 0

3 years ago

Read 2 more answers

Amy walks 32 m right and then 12 m left. She turns and walks another 28 m right and then turns and walks 7 m left. What is Amy's

Karo-lina-s [1.5K]

Her displacement is 41m. First, she walks 32m to the right, then 12m to the left. I subtract 12 from 32 to get 20m. She walks 28m to the right. Add 28 to 20 and you get 48. Finally, she walks 7m to the left. Subtract 7, then you get 41m.

4 0

4 years ago

¿Juan quiere calentar una barra de aluminio de 100 g, para realizar un trabajo. La temperatura ambiente es de 27°C pero necesita

Luda [366]

Answer:

709.5 cal

Explanation:

masa m de la barra de aluminio = 100 g

temperatura ambiente = 27 ° C

Asumiremos que la barra de aluminio está en equilibrio térmico con el ambiente.

Esto significa que la temperatura inicial de la barra es de 27 ° C

temperatura final a la que la barra debe calentarse = 60 ° C

el aumento de temperatura ΔT será

ΔT = 60 ° C - 27 ° C = 33 ° C

capacidad calorífica específica c del aluminio = 0.215 cal/g°C

Calor C requerido = mcΔT

C = 100 x 0.215 x 33 = 709.5 cal

8 0

3 years ago