Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form
is equal to

where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to

if
----> the <u>quadratic equation</u> has two <u>real roots</u>
if
----> the <u>quadratic equation</u> has one <u>real root</u>
if
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
Answer: to understand this we need a picture of the triangle, but without it I know that the only answer that is correct is the 3rd
Step-by-step explanation:
step 1
Find out the slope WX
W(2,-3) and X(-4,9)
m=(9+3)/(-4-2)
m=12/-6
m=-2
step 2
Find out the slope YZ
Y(5,y) and Z(-1,1)
m=(1-y)/(-1-5)
m=(1-y)/-6
m=(y-1)/6
step 3
Remember that
If two lines are perpendicular
then
their slopes are negative reciprocal
that means
(y-1)/6=1/2 -----> because the negative reciprocal of -2 is 1/2
solve for y
2y-2=6
2y=6+2
2y=8
<h2>y=4</h2>
Pretty sure the answer would be 1/A^4