Lithium and fluorine undergo ionic bonding. Using the noble gas electron configurations for each (below), please explain the pro
1 answer:
Answer:
Lithium loses one electron to fluorine and forms ionic bond, having formula .
Explanation:
Lithium is the element of the group 1 and period 2 which means that the valence electronic configuration is .
Fluorine is the element of the group 17 and period 2 which means that the valence electronic configuration is .
<u>Thus, lithium loses 1 electron and become positively charged. Fluorine on the other hand accepts this electron and become negatively charged.</u> This is done in order that the octet of the atoms are complete. <u>These both ions then form ionic bond as their will be electrostatic interaction between the two oppositely charged ions.</u>
Thus, the formula of calcium chloride is .
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%Mass
Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol
or
Answer:
24x10³
Explanation:
2CO₂(g) + 4H₂O(g) → 2CH₃OH(l) + 3O₂ (g)
The equilibrium constant for this reaction is:
Kc =
The expression of [CH₃OH] is left out as it is a pure liquid.
Now we <u>convert the given masses of the relevant species into moles</u>, using their <em>respective molar masses</em>:
- CO₂ ⇒ 3.28 g ÷ 44 g/mol = 0.0745 mol CO₂
- H₂O ⇒ 3.86 g ÷ 18 g/mol = 0.214 mol H₂O
- O₂ ⇒ 2.80 g ÷ 32 g/mol = 0.0875 mol O₂
Then we calculate the concentrations:
- [CO₂] = 0.0745 mol / 7.5 L = 0.0099 M
- [H₂O] = 0.214 mol / 7.5 L = 0.0285 M
- [O₂] = 0.0875 mol / 7.5 L = 0.0117 M
Finally we <u>calculate Kc</u>:
- Kc =
= 24x10³