Question

Lithium and fluorine undergo ionic bonding. Using the noble gas electron configurations for each (below), please explain the process of bonding step by step, using proper grammar and mechanics. Noble Gas Electron Configurations:________ Lithium:_______ [He] 2s1 Fluorine:______ [He] 2s22p5

Answer 1

Answer:

Lithium loses one electron to fluorine and forms ionic bond, having formula $LiF$.

Explanation:

Lithium is the element of the group 1 and period 2 which means that the valence electronic configuration is $[He]2s^1$.

Fluorine is the element of the group 17 and period 2 which means that the valence electronic configuration is $[He]2s^22p^5$.

Thus, lithium loses 1 electron and become positively charged. Fluorine on the other hand accepts this electron and become negatively charged. This is done in order that the octet of the atoms are complete.  These both ions then form ionic bond as their will be electrostatic interaction between the two oppositely charged ions.

Thus, the formula of calcium chloride is $LiF$.