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Anna007 [38]
3 years ago
13

How does molarity and molality affect the concentration of a solutionexplain.

Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0

Concentration of a solution can be expressed in terms of molarity and molality

Molarity is the number of moles of solute in a liter of a solution.

Molarity (M) = Moles of solute/Volume(litres) of solution

Molality is the number of moles of solute in one kg of the solution

Molality (m) = Moles of solute/Mass (kg) of solution

Therefore if the volume or the mass of the solution is changed this would affect the concentration.

In addition, volume is a quantity which depends on temperature. However, mass is independent of temperature. Therefore any changes in temperature, can also bring about a change in the molarity of the solution.


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Enter the chemical formula of a binary molecular compound of hydrogen and a Group 4A element that can reasonably be expected to
irakobra [83]

Answer: GeH4 (Germanium(IV) Hydride)

Explanation:

A Binary molecular compound Hydrogen and a Group 4A element which is more more acidic than SiH4 in aqueous solution is GeH4.

The pKa of GeH4;

= 25

Whilst that of SiH4

= 35

The lesser the pKa the higher the Ka which means more acidic.

6 0
2 years ago
Many homeowners treat their lawns with CaCO3(s) to reduce the acidity of the soil. Write a net ionic equation for the reaction o
Agata [3.3K]

The reaction of acid, assuming HCl and calcium carbonate always produces a gas. The reaction is as follows:
2 HCl + CaCO3 --> CaCl2 + H2CO3 
H2CO3, carbonic acid, is a weak acid that is unstable in water solutions at high concentrations. As such, it decomposes: 
H2CO3 --> H2O + CO2 
Then, 
2 HCl + CaCO3 --> CaCl2 + H2O + CO2 
The total ionic equation looks as follows: 
2H+(aq) + 2 Cl-(aq) + CaCO3(s) --> Ca+2(aq) + 2 Cl-(aq) + H2O(l) + CO2(g) 
Clearly, Cl- is a spectator ion as it is unchanged in the reaction. The net ionic reaction looks as follows: 
2 H+(aq) + CaCO3(s) --> Ca+2(aq) + H2O(l) + CO2(g)
4 0
3 years ago
A mixture of hydrogen (2.02 g) and chlorine (35.90 g) in a container at 300 K has a total gas pressure of 748 mm Hg. What is the
Llana [10]

The partial atmospheric pressure (atm) of hydrogen in the mixture is 0.59 atm.

<h3>How do we calculate the partial pressure of gas?</h3>

Partial pressure of particular gas will be calculated as:

p = nP, where

  • P = total pressure = 748 mmHg
  • n is the mole fraction which can be calculated as:
  • n = moles of gas / total moles of gas

Moles will be calculated as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

Moles of Hydrogen gas = 2.02g / 2.014g/mol = 1 mole

Moles of Chlorine gas = 35.90g / 70.9g/mol = 0.5 mole

Mole fraction of hydrogen = 1 / (1+0.5) = 0.6

Partial pressure of hydrogen = (0.6)(748) = 448.8 mmHg = 0.59 atm

Hence, required partial atmospheric pressure of hydrogen is 0.59 atm.

To know more about partial pressure, visit the below link:
brainly.com/question/15302032

#SPJ1

3 0
1 year ago
Help with this worksheet please (24pts)
Igoryamba
  • Atoms that loss or gain electrons are called ions. There are two types of ions: cations and anions.
  • Here, 2+ represents that Calcium (Ca) should gain 2 more electrons so that its number equals to that of protons.
  • 3- represents that Nitrogen (N) should loss 3 electrons to equivalent with the number of protons.
  • Here, anions are S^2-, P^3-, Se^2-, Br^-.
  • While cations are Cr^3+, Ag^+, Li^+, Ba^2+.
  • The number of protons of Magnesium (Mg) = 12
  • The number of nuetrons of Mg = 12
  • The number of electrons of Mg = 12

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
2 years ago
A gas has a volume of 3.25 liters at 54 C and 231 kPa of pressure. At what temperature will the same gas take up 4.35 liters of
Firdavs [7]

Answer: 318 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 231 kPa

P_2 = final pressure of gas = 168 kPa

V_1 = initial volume of gas = 3.25 L

V_2 = final volume of gas = 4.35 L

T_1 = initial temperature of gas = 54^oC=273+54=327K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{231\times 3.25}{327}=\frac{168\times 4.35}{T_2}

T_2=318K

At 318 K of temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa

4 0
3 years ago
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