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Anna007 [38]
3 years ago
13

How does molarity and molality affect the concentration of a solutionexplain.

Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0

Concentration of a solution can be expressed in terms of molarity and molality

Molarity is the number of moles of solute in a liter of a solution.

Molarity (M) = Moles of solute/Volume(litres) of solution

Molality is the number of moles of solute in one kg of the solution

Molality (m) = Moles of solute/Mass (kg) of solution

Therefore if the volume or the mass of the solution is changed this would affect the concentration.

In addition, volume is a quantity which depends on temperature. However, mass is independent of temperature. Therefore any changes in temperature, can also bring about a change in the molarity of the solution.


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Answer:

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6 0
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What is the molarity of a solution that contains 0.400 mol HCI in 9.79 L solutions ​
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Molarity's formula is known as: Molarity(M)=moles of solute/liters solution.

In this case we are already given moles and liters so you just have to plug the numbers into the equation.

0.400 mol HCL/9.79L solution=0.040858M

If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.

6 0
3 years ago
Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea
galina1969 [7]

Answer:

Cd(s) + AgNO₃(aq)  → Cd(NO₃)₂ (aq) + Ag(s)

Oxidized: Cd

Reduced: Ag

Explanation:

Cd(s) + AgNO₃(aq)  → Cd(NO₃)₂ (aq) + Ag(s)

Cd → Cd²⁺  +  2e⁻      Half reaction oxidation

1e⁻ + Ag⁺ → Ag           Half reaction reduction

Ag changed oxidation number from +1 to 0

Cd changed oxidation number from 0 to +2

Let's ballance the electrons

( Cd → Cd²⁺  +  2e⁻ ) .1

( 1e⁻ + Ag⁺ → Ag ) .2

Cd + 2e⁻ + 2Ag⁺  → 2Ag +  Cd²⁺  +  2e⁻

Finally the ballance equation is:

Cd(s) + 2AgNO₃(aq)  → Cd(NO₃)₂ (aq) + 2Ag(s)

4 0
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