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Morgarella [4.7K]
3 years ago
5

What's the square root of 2 million

Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0
One million i believe dont you just half for square roots???

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The range of the following relation R{(3,-2), (1, 2), (-1, -4), (-1, 2)} is O{-1.1,3) -1,-1,1.3 01-4, 2, 2, 2] {-4, -2, 2​
maw [93]

Answer:

The range is -2,2,-4

Step-by-step explanation:

hope this helps

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3 years ago
If QR=PQ , RS=PQ and QR is 2x+5 and RS is 10-3x Solve for x using the given information
AfilCa [17]

Answer:

x = 1

Step-by-step explanation:

2x + 5 = 10 - 3x

2x + 3x = 10 - 5

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Factor the expression.<br> x squared-25
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3 years ago
Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29
Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

⇒ \frac{15}{Sin 29} = \frac{20}{sin B}

Using value of sin 29°

⇒ \frac{15}{0.49} = \frac{20}{sin B}

Cross multiplying both side.

⇒ Sin B= \frac{20\times 0.49}{15} = 0.65

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ 29+41+B= 180

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

\frac{b}{SinB} = \frac{c}{SinC}

⇒\frac{20}{sin41} = \frac{C}{sin110}

Using the value of sine and cross multiplying both side.

⇒ C= \frac{20\times 0.94}{0.65} = 28.92

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= (15+20+28.92)= 63.9

∴ Perimeter of triangle= 63.9 units

7 0
3 years ago
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