Question

A rectangle has a height of k^2+3 and a width of k^2 +7 what is the area

Answer 1

Answer:

$({k}^{2} + 3) \times( {k}^{2} + 7) \\ = {k}^{4} + 7 {k}^{2} + 3 {k}^{2} + 21 \\ = {k}^{4} + 10 {k}^{2} + 21$