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3 years ago

How do you solve -2(6x+3)=-27–5x ?

1 answer:

8 0

Hi!

Our goal is to isolate x on one side by doing the same operation on both sides.

First let's use the distribution property.
-2 x 6 = -12
-2 x 3 = -6
-12x - 6 = -27 - 5x

Add 6 to both sides
-12x - 6 + 6 = -27 + 6 - 5x
-12x = -21 - 5x

Add 5x to both sides
-12x + 5x = -21 - 5x + 5x
-7x = -21

Divide by -7 on both sides
-7x/-7 = -21/-7
x = 3

The answer is x = 3

Hope this helps! :)

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3 inches of water when the tub is filled for a minute

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3 years ago

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8.33333333. You know you can use a calculator.

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3 years ago

A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

3 0

3 years ago

The state of New Jersey makes approximately $1.55 billion annually from tolls of the $1.55 billion about 3/4 comes from tolls on

Rama09 [41]

Percent of turn pike is 75% and percent of parkway is 25%.

Solution:

Given, The state of New Jersey makes approximately $1.55 billion annually from tolls of the $1.55 billion

About $\frac{3}{4}$ comes from tolls on the turnpike

Remaining $\frac{1}{4}$ comes from tolls on the parkway

To find the percent of the total revenue from turnpike:

$\begin{array}{l}{\text { Percent of turnpike }=\frac{\text { amount from parkway }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{3}{4} \text { of total revenue }}{\text { tot al revenue }} \times 100} \\\\ {=\frac{\frac{3}{4} \times \text { total revenue }}{\text { total revenue }} \times 100} \\\\ {=\frac{3}{4} \times 100=3 \times 25=75 \%}\end{array}$

To find the percent of the total revenue from parkway:

$\begin{array}{l}{\text { Percent of parkway }=\frac{\text { amount from parkway }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{1}{4} \text { of total revenue }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{1}{4} \times \text { total revenue}}{\text { total revenue }} \times 100} \\\\ {=\frac{1}{4} \times 100=25 \%}\end{array}$

Summarizing the results:

Percent of turn pike is 75%

Percent of parkway is 25%

3 0

3 years ago

What is the vertex of this equation y = -x^2+ 3

Svetach [21]

Answer: (0,3)

Step-by-step explanation: To find the x-value of the vertex for any quadratic, you can use the formula -b/2a. In this case, there is no clear b, but you can think of it like y=-x^2 +0x+3 so in the form ax^2 + bx +c, b=0. Therefore the x-value is 0/ -2, or 0. So we know the vertex is (0, y). To find y, just plug 0 into the original equation for x, getting you y=0+3, so y=3, so the vertex is (0,3)

4 0

3 years ago