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Leona [35]
3 years ago
5

Determine in which quadrant the product of 5(cos3pi/8 + isin 3pi/8) and sqrt 2(cos pi/12 + sin pi/12) lies.

Mathematics
1 answer:
ohaa [14]3 years ago
6 0
When you multiply two complex numbers given in polar form, the argument of the product is the sum of the arguments of the factors. Meanwhile, the modulus of the product is the product of the moduli of the factors.


In this case, you'd have

\dfrac{3\pi}8+\dfrac\pi{12}=\dfrac{11\pi}{24}

and the modulus would simply be 5\sqrt2. Since

\dfrac{11\pi}{24}

we would expect the final product to fall in the first quadrant.
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Consider the following pair of equations:
Aloiza [94]
Y = 3x + 3 this is equation 1
y = x -1 this is equation 2
since equation 1 and 2 already defined y in terms of x, we're just gonna substitute y into the other equation. as 2 is shorter I'm going with that today
x - 1 = 3x +3
-1 - 3 = 3x - x
-4 = 2x
x = -2
now we've got x just sub it in equation 2
y = -2 -1
y = -3
so the answer is (-2,-3)

5 0
3 years ago
Hana's height is given as 162 cm, correct to the nearest cm.
SashulF [63]

Answer:

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6 0
3 years ago
Joe has 14 toys in a collection he buys 12 new toys and sells 8 out of the old collection would you subtract 26-8 which would gi
NeTakaya

Answer:

yes I think that's right because 14-12=26 so if you subtract 26 from 8 which that will give you 18

4 0
3 years ago
Use an equivalent fraction to find the sum of 4/10 + 28/100
kipiarov [429]
Hi there!

4/10 = (4*10)/(10*10) = 40/100

40/100 + 28/100 = 68/100

68/100 = 34/50 = 17/25

Hope this helps!
4 0
3 years ago
Read 2 more answers
3(4x^2y^3 + 2x^3) – 4(9x^3y^2 – 6x^2y^3)<br> How to solve pls?
babunello [35]

Answer:

3(4 {x}^{2}  {y}^{3} + 2 {x}^{3}) - 4(9 {x}^{3}  {y}^{2}  - 6 {x}^{2}  {y}^{3} ) \\  = (12 {x}^{2}  {y}^{3}  + 6 {x}^{3} ) - (36{x}^{3}  {y}^{2} - 24{x}^{2}  {y}^{3}) \\  = (12 {x}^{2}  {y}^{3}  + 6 {x}^{3} )  +  ( - 36{x}^{3}  {y}^{2}  +  24{x}^{2}  {y}^{3}) \\  = - 36{x}^{3}  {y}^{2}  + 36x^{2}  {y}^{3} + 6 {x}^{3}

I hope I helped you^_^

4 0
3 years ago
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