Answer:
B
Step-by-step explanation:
number two is the answer because the others dont work
Answer:
lxwxh
Step-by-step explanation:
I don't know the answer but someone who does will tell you.
Answer:
B. 13.3
Step-by-step explanation:
Given:
AM = 6
MB = 4
AN = 8
Since ∆ABC ~ ∆AMN, therefore:
AB/AM = AC/AN
AB = AM + MB = 6 + 4 = 10
AC = AN + NC = 8 + NC
Plug in the values into the equation
10/6 = (8 + NC)/8
5/3 = (8 + NC)/8
Cross multiply
8*5 = 3(8 + NC)
40 = 24 + 3NC
40 - 24 = 3NC
16 = 3NC
Divide both sides by 3
5.3 = NC
NC = 5.3
✅AC = 8 + NC
Plug in the value of NC
AC = 8 + 5.3
AC = 13.3
Hi there! the best way of solving this is picturing out what the graph might look like. Let's assume you had the graph of a parabola y=x^2. You know that for every x you substitute, there'd always be a value for y. Thus, the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. The range on the other hand is different. We know that any number raised to the second power will always yield a positive integer or 0. Thus, y=x^2 won't have any negative y-values as the graph opens upward. Therefore, the range is: ALL REAL NUMBERS GREATER THAN OR EQUAL TO 0. or simply: 0 to +INFINITY.
<span>On the other hand, a cubic function y=x^3 is quite different from the parabola. For any x that we plug in to the function, we'd always get a value for y, thus there are no restrictions. And the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. For the y-values, the case would be quite similar but different to that of the y=x^2. Since a negative number raised to the third power gives us negative values, then the graph would cover positive and negative values for y. Thus, the range is ALL REAL NUMBERS or from -INFINITY to + INFINITY. Good luck!!!:D</span>