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Marta_Voda [28]
4 years ago
15

how do intra-specific and inter-specific relationships within a community maintain biodiversity by preventing competitive exclus

ion?
Chemistry
1 answer:
Irina-Kira [14]4 years ago
6 0

One species will often exhibit an advantage in resource use. This superior competitor will out-compete the other with more efficient use of the limiting resource. As a result, the inferior competitor will suffer a decline in population over time. It will be excluded from the area and replaced by the superior competitor. Without it and having intra-specific and inter-specific relationships in a community will lead to a harmonious community and maintain the biodiversity.

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3.50 liters of a gas at 727.0 K will occupy how many liters at 153.0 K?
miv72 [106K]

Answer:

0.737 L

Explanation:

Charles law states for a fixed amount of gas, volume of the gas is directly proportional to the absolute temperature of the gas at constant pressure

we can use the following equation

V1/T1 = V2/T2

where V1 is volume and T1 is temperature at first instance

V2 is volume and T2 is temperature at the second instance

substituting the values

3.50 L / 727.0 K = V2 / 153.0 K

V2 = 0.737 L

new volume at 153.0 K is 0.737 L

8 0
4 years ago
Which physical property can be measured??
Nikitich [7]
Extensive property (like volume and mass), can be measured.
4 0
3 years ago
Read 2 more answers
Why are vials made from vapor glass stronger then typical vials?
Drupady [299]

Answer:

2

Explanation:

I'm not that sure plz tell me if this is right

6 0
3 years ago
How many grams of aluminum are required to give a total dislocation length of 3,000 miles (enough to stretch from New York City
Luba_88 [7]

Answer:

0.13 g

Explanation:

mass of aluminum required = ( Dislocation length) / ( Dislocation density) × (density of metal)

3000 miles to cm (  1 mile = 160934 cm) = 3000 miles ×  160934 cm / 1 mile = 482802000 cm

density of Aluminium = 2.7 g /cm³

dislocation density of aluminum = 10¹⁰ cm³

mass of aluminum required = (482802000 cm × 2.7 g/cm³) / 10¹⁰ cm³ = 0.13 g

5 0
3 years ago
You are examining decomposition of corn leaves following the growing season on a farm. To do this, you place 33 g of corn leaves
m_a_m_a [10]

Answer:

c. 9.94 g

Explanation:

From the question,

Using

mt = m₀e⁻kt.................... Equation 1

Where mt = mass of the leaf remaining in the bag, m₀ = original mass of leave that was placed in the bag, k = decay constant, t = time.

Given: m₀ = 33 g, k = 0.04, t = 30 days.

Substitute into equation 1

mt = 33(e⁻(0.04ˣ30))

mt = 33e⁻¹²/¹⁰

mt = 33/e¹²/¹⁰

mt = 33/3.320

mt = 9.94 g.

Hence the right answer is c. 9.94 g

8 0
4 years ago
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