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maria [59]
3 years ago
9

How many grams of aluminum are required to give a total dislocation length of 3,000 miles (enough to stretch from New York City

to Los Angeles assuming you could align all the dislocations into a single line like a string). Assume the dislocation density of aluminum is 1010cm/cm3.
Chemistry
1 answer:
Luba_88 [7]3 years ago
5 0

Answer:

0.13 g

Explanation:

mass of aluminum required = ( Dislocation length) / ( Dislocation density) × (density of metal)

3000 miles to cm (  1 mile = 160934 cm) = 3000 miles ×  160934 cm / 1 mile = 482802000 cm

density of Aluminium = 2.7 g /cm³

dislocation density of aluminum = 10¹⁰ cm³

mass of aluminum required = (482802000 cm × 2.7 g/cm³) / 10¹⁰ cm³ = 0.13 g

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Answer:

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Explanation:

Step 1: Data given

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Step 2: The balanced equation

Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4

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For 1 mol Ca(OH)2 we need 1 mol H2SO4 to produce 2 moles H2O and 1 mol CaSO4

For 25.0 moles H2SO4 we'll need 25.0 moles Ca(OH)2 to produce 50 moles H2O and 25.0 moles CaSO4

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Volume Ca(OH)2 = 17.2 L

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When the following equation is balanced, what is the coefficient for NaNO3?
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<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  

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Reaction

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