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3 years ago

Which physical property can be measured??

Chemistry

2 answers:

Scorpion4ik [409]3 years ago

5 0

Answer:

Density for Edge

Explanation:

Density is the only choice that has a numerical answer.

Nikitich [7]3 years ago

4 0

Extensive property (like volume and mass), can be measured.

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*PLEASE HELP ASAP*

dimulka [17.4K]

I believe its true , because when two elements form different compounds a given mass of one element will combine with the other , during any chemical change atoms arent created or destroyed they are jus rearranged

5 0

4 years ago

Azithromycin suspension dosing is 10 mg/kg/d and is available in 200mg/5ml doses. how many ml would a 25kg child receive daily?

bekas [8.4K]

The answer to this question is 6.25ml

To answer this question, you need to calculate the azithromycin drug doses for this patient. The calculation would be: 25kg * 10mg/kg/d= 250mg/d

Then multiply the doses with the available drug. It would be:
250 mg/d / (200mg/5ml)= 6.25ml/d

8 0

4 years ago

Part B Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution

MissTica

Answer:

0,508g of H₂O₂

Explanation:

For the reaction:

2KMnO₄(aq) + H₂O₂(aq) + 3H₂SO₄(aq) → 3O₂(g) + 2MnSO₄(aq) + K₂SO₄(aq) + 4H₂O(l)

2 moles of KMnO₄ react with 1 mol of H₂O₂.

In the titration, moles of KMnO₄ required were:

1,68M×0,0178L = 0,0299 moles of KMnO₄. Moles of H₂O₂ are:

0,0299 moles of KMnO₄× $\frac{1molH_{2}O_{2}}{2molKMnO_{4}}$ = 0,01495 moles of H₂O₂. As molar mass of H₂O₂ is 34,01g/mol, mass of H₂O₂ was dissolved is:

0,01495 moles of H₂O₂× $\frac{34,01g}{1molH_{2}O_{2}}$ = <em>0,508g of H₂O₂</em>

5 0

3 years ago

The equilibrium constant for the reaction 2NO(g)+Br2(g)⥫⥬==2NOBr(g) is Kc=1.3×10−2 at 1000 K. At this temperature does the equil

o-na [289]

Answer :

The equilibrium favors NO and $Br_2$ .

(1) The value of equilibrium constant for this reaction is, 76.9

(2) The value of equilibrium constant for this reaction is, 8.77

Explanation:

The given chemical equation is:

$2NO(g)+Br_2(g)\rightarrow 2NOBr(g)$

The value of equilibrium constant for the above equation is $K_c=1.3\times 10^{-2}$ .

The value of $K_c$ that means equilibrium lies to the left side. Thus, the equilibrium favors NO and $Br_2$ .

We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:

(1) $2NOBr(g)\rightarrow 2NO(g)+Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_1}=\frac{1}{K_c}$

$K_{c_1}=\frac{1}{1.3\times 10^{-2}}=76.9$

Thus, the value of equilibrium constant for this reaction is, 76.9

(2) $NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '1/2', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_2}=(\frac{1}{K_c})^{1/2}$

$K_{c_2}=(\frac{1}{1.3\times 10^{-2}})^{1/2}=8.77$

Thus, the value of equilibrium constant for this reaction is, 8.77

7 0

3 years ago

Read 2 more answers

When elements combine to form compounds does there properties change?

Amiraneli [1.4K]

Yes, they do. The process described is a chemical reaction and it implies the change of nature of reactants and, of course, the change of its properties.

7 0

3 years ago