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3 years ago

Simplify. Assume that no denominator is equal to zero.

Mathematics

2 answers:

nikklg [1K]3 years ago

8 0

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{(2a^7b)^2}{32b^6}\implies \cfrac{(2^2a^{7\cdot 2}b^2)}{32b^6}\implies \cfrac{4a^{14}b^2}{32b^6}\implies \cfrac{a^{14}}{8b^6b^{-2}}\implies \cfrac{a^{14}}{8b^{6-2}}\implies \cfrac{a^{14}}{8b^4}$

exis [7]3 years ago

4 0

Answer:

c is the answer

Step-by-step explanation:

All work is shown and pictured

You might be interested in

4x+20 3x determine the value of x

nlexa [21]

Step-by-step explanation:

$4x + 20 = 3x \\ x = - 20$

<h2>-20 is the right answer.</h2>

5 0

3 years ago

Solve the following initial-value problem: (ex+y)dx+(3+x+yey)dy=0, y(0)=1 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

3 years ago

How many ways can 5 people be arranged in a line?

Rasek [7]

Answer: 120 ways

Step-by-step explanation: In this problem, we're asked how many ways can 5 people be arranged in a line.

Let's start by drawing 5 blanks to represent the 5 different positions in the line.

Now, we know that 5 different people can fill the spot in the first position. However, once the first position is filled, only 4 people can fill the second spot and once the second spot is filled, only 3 people can fill the third spot and so on. So we have 5 4 3 2 1.

Now, based on the counting principle, there are 5 x 4 x 3 x 2 x 1 ways for all 5 spots to be filled.

5 x 4 is 20, 20 x 3 is 60, 60 x 2 is 120, and 120 x 1 is 120.

So there are 120 ways for all 5 spots to be filled which means that there are 120 ways that 5 people can be arranged in a line.

I have also shown my work on the whiteboard in the image attached.