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3 years ago

Jessica bought 10 pieces of candy at the store. She spent $8.60. How much did each piece of candy cost?

Mathematics

2 answers:

Tema [17]3 years ago

8 0

$0.86. You either divide by 10 manually, or use the powers of 10.

andrezito [222]3 years ago

8 0

Answer:

Each piece of candy cost

$0.86

Step-by-step explanation:

Step one This problem bothers on well we can do and understand our division of numbers

Step two

Given that Jessica spent $8.60

To buy 10 pieces of candy

Step three

We can get the unit cost of each candy by simply divide the total amount spent by the total Candy purchased

Hence

A candy cost = 8.60/10

= $0.86

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Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

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Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

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This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

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slavikrds [6]

Its B
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