Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
= Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).
If you're just asking for how that'd look in algebraic form then the answer would be v+50/2
The rule for differentiation for variable with exponents has the formula:
d/dx (xⁿ) = nxⁿ⁻¹
where n is the exponent
Thus, for the given equation, the solution is as follows:
y = 2x²
dy/dx = 2(2)x²⁻¹ = <em>4x
Thus, the derived equation of the given would now be 4x.</em>
The students on the right hand side had better overall results
There were less people on the left hand side of the room this affects the average even with the right hand side having two zeros, another thing which the left hand side didn’t have.
Hope I helped
Answer:
Option A True
Step-by-step explanation:
we know that
The sum of the internal angles of the triangle is equal to 
<u>In the triangle JKL</u>
m∠L=
so
The measurements of the angles of triangle JKL are 
<u>In the triangle WXY</u>
m∠W=
so
The measurements of the angles of triangle WXY are
therefore
Triangle JKL and triangle WXY are similar by AAA ( The AAA postulate states that if you can prove that all three angles of two triangles are congruent, you can prove the two triangles are similar)
