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Rudik [331]
3 years ago
14

Which shows the numbers in order from least to greatest? 

Mathematics
2 answers:
Artemon [7]3 years ago
7 0
D.

1 3/7 = 1.43

therefore from least to greatest it would need to be 
1.38,1.4,1.43

or in the question

1.38, 1.4, 1 3/7

Therefore the answer would be D.

Hope this helps!
Andrei [34K]3 years ago
6 0
D. because 1 3/7 is equal to 1.42..... it's bigger than 1.38 and 1.4 and 1.4 is bigger than 1.38.
hope that helps!
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Orlov [11]
8.03 times 10^5 or
8.03e+05
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3 years ago
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The sum or difference of p and q is the of the x-term in the trinomial.​
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2 years ago
The length of a rectangle is six times its width. If the area of the rectangle is 384^2, find its perimeter.
Leno4ka [110]

Answer:

Perimeter, P = 112 meters

Step-by-step explanation:

  • Let the length of the rectangle be L.
  • Let the width of the rectangle be W.

Translating the word problem into an algebraic expression, we have;

L = 6W  ...... equation 1

<u>Given the following data;</u>

  • Area of rectangle = 384 m²

To find the perimeter of the rectangle;

First of all, we would determine the dimensions of the rectangle using its area.

Mathematically, the area of a rectangle is given by the formula;

Area of rectangle = LW  ..... equation 2

Substituting eqn 1 into eqn 2, we have;

384 = 6W(W)

384 = 6W²

Dividing both sides by 6, we have;

W² = 384/6

W² = 64

Taking the square root of both sides, we have;

W = √64

Width, W = 8 meters

Next, we would find the length;

L = 6W

L = 6 * 8

Length, L = 48 meters

Lastly, we would determine the perimeter of the rectangle using the above dimensions;

Mathematically, the perimeter of a rectangle is given by the formula;

Perimeter = 2(L + W)

Substituting the values into the formula, we have;

Perimeter, P = 2(48 + 8)

Perimeter, P = 2(56)

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PLEASE ANSWER QUICK!!!SHOW STEPS
Vedmedyk [2.9K]
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5b. For the general equation y = a cos(bx), the amplitude is given by a. Therefore the amplitude is a = 1/4, and this means that the cosine wave's range is from -1/4 to 1/4 for all values of x.
5c. The equation of the midline is y = 0. This represents the average value over the wave. This is determined by adding the highest and lowest values of the range and taking the average, in this case, 1/4 + (-1/4) = 0, and 0 / 2 = 0. Another way to do this is using the general equation y = a cos(bx) + c, where the midline's equation is y = c. In this case, there is no value of c in the given, implying that c = 0, and the midline is y = 0.

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