What else would need to be congruent to show that ABC = XYZ by ASA?

1 answer:

5 0

The answer would be A because line CB is equivalent to ZY tight? And angles Z and C are congruent. We also know that they are congruent by a ASA relationship, <u><em>so then angles Y and B are congruent, the answer is A.</em></u>

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Correct 24.3318 to two decimal places

aliina [53]

24.33 is the answer to this question

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What is the 6th term of the geometric sequence f(1) = 12, f(n) = -2/3f(n-1)

Troyanec [42]

$\bf \begin{array}{ccll}
\stackrel{n^{th}}{term}&value\\\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\\\
1&12\\\\
2&-\frac{2}{3}f(2-1)\\\\
&-\frac{2}{3}f(1)\\\\
&-\frac{2}{3}(12)\\\\
&-8\\\\
3&-\frac{2}{3}f(3-1)\\\\
&-\frac{2}{3}f(2)\\\\
&-\frac{2}{3}(-8)\\\\
&\frac{16}{3}
\end{array}$

$\bf \begin{array}{cccl}
\qquad &\qquad \\
4&-\frac{2}{3}f(4-1)\\\\
&-\frac{2}{3}f(3)\\\\
&-\frac{2}{3}\left( \frac{16}{3} \right)\\\\
&-\frac{32}{9}\\\\
5&-\frac{2}{3}f(5-1)\\\\
&-\frac{2}{3}f(4)\\\\
&-\frac{2}{3}\left( -\frac{32}{9} \right)\\\\
&\frac{64}{27}\\\\
6&-\frac{2}{3}f(6-1)\\\\
&-\frac{2}{3}f(5)\\\\
&-\frac{2}{3}\left( \frac{64}{27}\right)
\end{array}$

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3 years ago

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katrin [286]

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