The unbalanced equation is BF3 + Li2 SO3 --> B2 (SO3)3 + LiF, where the numbers to the right of the symbols are subscripts. The balanced equation is 2 BF3 + 3 Li2SO3 ---> B2 (SO3)3 + 6LiF. The numbers in front of every formula (compound) are the respective coefficients. You can check that the equation is balanced counting every element: There are 2B in the side of the reactants and 2B in the side of the products; there are 6F in the side of the reactants and 6F in the side of the products; there are 6 Li in the side of the reactants and 6 Li in the side of the products; and there are 3 SO3 in the side of the reactants and 3 SO3 in the side of the products. <span>So, the coefficient of the LiF is 6.</span>
The trampoline's elastic potential energy is transformed into kinetic energy when it returns to its original position.
The ball's gravitational potential energy become kinetic energy when it drops. Pls give brainliest
Answer:
See explanation
Explanation:
From the analysis we have in the question, we must look towards a first row transition metal ion having a d^6 configuration because it yields a paramagnetic complex having four unpaired electrons and a diamagnetic complex having no unpaired electrons.
We have two possible candidates in mind, Fe^2+ and Co^3+. However, Fe^2+ does not form as many coloured complexes as stated in the question so we have to eliminate that option.
We are now left with only Co^3+. Various ligands are going to cause these various colours of Co^3+ to appear in solution.
Hence, we can deduce from all these that the nature of ligands determines the colour of the complex . Don't forget that the colour of a complex arises from crystal field splitting.
Answer:
All of the above.
Explanation:
In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.
When a solution is non ideal then it shows positive or negative deviation.
Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is
and vapour pressure of component B is
.
= Vapour pressure of component A in pure form
= Vapour pressure of component B in pure form
=Mole fraction of component A
=Mole fraction of component B
The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.
,
Therefore, 
Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.
Hence, option a,b,c and d are true.
no, it contains 3 basic particles. (protons, electrons, neutrons)
hope this helped