HA ⇄ H⁺ + A⁻
so:
![\frac{[H^+][A^-]}{[HA]} = 1.5 x 10^{-5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D%20%3D%201.5%20x%2010%5E%7B-5%7D%20%20)
and now:
= 1.5 x 10⁻⁵
x is considered very small compared to 0.15
x² = 2.25 x 10⁻⁶
x = 1.5 x 10⁻³
So [H⁺] = 1.5 x 10⁻³
pH = - log [H⁺] = - log (1.5 x 10⁻³) = 2.83
Answer:
0° Celsius
Explanation:
The thermometer shows 0° Celsius which corresponds to 32° F.
Which eclipse was modeled when the large ball was between the small ball and the light?
The model is a "Lunar Eclipse" (If it was talking about the earth, then yes, it is a lunar eclipse).
<u> </u>
Which eclipse was modeled when the small ball was between the large ball and the light?
The model is a "Solar Eclipse".
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What does the large ball represent?
The earth.
<u> </u>
What does the small ball represent?
The moon.
<u> </u>
What does the light source represent?
The sun.
Hope this helps!~ <3
(I can't draw so sorry.)
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Answer:
Explanation:
1. The reaction will proceed backward, shifting the equilibrium position to the left.
2. The reaction will proceed forward, shifting the equilibrium position to the right.
3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)
<span>
1. Remember (sum of products) - (sum of reactants)
So ΔHrxn = 2 ΔHf [H2(g)] + ΔHf [Ca(OH)2(s)] - 2 ΔHf [H2O(l)] - ΔHf [Ca(s)]
= 2*0 + -986.09 kJ/mol - 2*(-285.8 kJ/mol) - 0
Do the math and you'll have the answer. BTW the ΔHf [H2(g)] and ΔHf
[Ca(s)] were 0 because these are elements in their standard states.
</span>HOPE THIS HELPS ;)
