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3 years ago

The term Reuther Ford gave to the positively charged particles in the nucleus of an antom was

1 answer:

4 0

<span>The</span> term Rutherford gave to the positively charged particles in the nucleus of an atom was/is Proton.

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What is the concentration of a 1:10 dilution of a 2.5 M solution of NaCl? How would you prepare exactly 100 ml of such a solutio

Marina CMI [18]

<u>Answer:</u> The concentration of the solution is 0.25 M

<u>Explanation:</u>

Let the volume of solution of 2.5 M NaCl be 10 mL

We are given:

Dilution ratio = 1 : 10

So, the solution prepared will have a volume of = $\frac{10}{1}\times 1000=100mL$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated NaCl solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted NaCl solution

We are given:

$M_1=2.5M\\V_1=10mL\\M_2=?M\\V_2=100mL$

Putting values in above equation, we get:

$2.5\times 10=M_2\times 100\\\\M_2=\frac{2.5\times 10}{100}=0.25M$

Hence, the concentration of the solution is 0.25 M

6 0

4 years ago

Ethanoic acid, CH3COOH, ionizes to form an ethanoate ion (CH3COO-) in aqueous solution. what else does it form? is it a monoprot

barxatty [35]

Ethanoic acid ionizes in aqueous solutions to form two ions which are $CH_3COO^-$ and $H^+$

<h3>Ionization of ethanoic acid</h3>

Ethanoic acid goes by the chemical formula $CH_3COOH$ .

In aqueous solutions, it ionizes as a monoprotic acid according to the following equation:

$CH_3COOH ---- > CH_3COO^- + H^+$

A monoprotic acid is an acid that is able to donate only a proton. Hence, ethanoic acid is said to be monoprotic because it ionizes in aqueous solutions to produce a single $H^+$

More on ethanoic acid can be found here: brainly.com/question/9991017

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8 0

2 years ago

What type of reaction is shown below? <br>a) Addition reaction <br>b) Esterification

Gemiola [76]

Answer:

a) Addition reaction, is your answer

6 0

3 years ago

What are the steps of natural selection?

blagie [28]

Answer:

The five steps involved in the process of natural selection are

Variation • Inheritance • Selection • Time • Adaptation

☆anvipatel77☆

•Expert•

Brainly Community Contributor

5 0

2 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion= $\frac{Volume}{Time}$

Effusion rate of oxygen gas after time t = $E=\frac{4.64 mL}{t}$

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = $E'=\frac{3.12 mL}{t}$

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{E}{E'}=\sqrt{\frac{M'}{M}}$

$\frac{\frac{4.64 mL}{t}}{\frac{3.12 mL}{t}}=\sqrt{\frac{M'}{32 g/mol}}$

M' = 70.77 g/mol

70.77 g/mol is the molar mass of the unknown gas.

8 0

3 years ago