1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svet_ta [14]
3 years ago
14

Rotational dynamics physics question please help.

Physics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
Looking at the force-time graph, wouldn't the force be integral fdt between 0 and 10s, a sort of "smoothed out pulse" ? And it looks like a familiar bell shaped curve. doesn't that produce a turning effect/torque and isn't there something about a circular analogue to F=ma in newtonian linear mechs ???
Looks like a difficult question for 5 points
You might be interested in
Please help with this question!!!!
Maslowich
The answer is B hope this helps
4 0
3 years ago
A 1/10th scale model of an airplane is tested in a wind tunnel. The reynolds number of the model is the same as that of the full
trasher [3.6K]

Answer:

of the velocity of a full size plane in the air

7 0
4 years ago
A cosmic-ray electron moves at perpendicular to earth’s magnetic field at an altitude where the field strength is. what is the r
Harlamova29_29 [7]

4.266 m is the radius of the circular path the electron follows.

Given

Speed of electron (v) = 7.5 × 10⁶ m/s

Earth's Magnetic Field (B) = 1 × 10⁻⁵ T

We already know that

Mass of electron (m) = 9.1 × 10⁻³¹ kg

Charge on electron (q) = 1.6 × 10⁻¹⁹ C

According to the formula

Radius of circular path(r) = mass on electron × speed/ Charge × Magnetic field

Radius of circular path(r) = m × v/q × B

Put the values into the formula

r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵

On solving, we get

r = 4.266 m

Hence, 4.266 m is the radius of the circular path the electron follows.

Learn more about magnetic field here brainly.com/question/26257705

#SPJ4

6 0
1 year ago
Serena drops a 5-kg book down the stairwell. What is the book's final velocity vf after it falls
elena55 [62]

Answer:

39.2m/s

Explanation:

Given parameters:

Mass of book  = 5kg

Time taken for fall  = 4s

Unknown:

Final velocity of the book  = ?

Solution:

Serena dropped the book from rest therefore, the initial velocity of the book is 0.

 Let us find the appropriate motion equation to solve this problem;

        V  = U + gt

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity  = 9.8m/s²

t is the time taken

  Insert the given parameters and solve;

       V = 0 + 9.8 x 4  = 39.2m/s

3 0
3 years ago
Predict the products of the combustion of methanol, CH3OH(l).
gregori [183]

Answer:

Carbon dioxide and water

Explanation:

The products of complete combustion are always carbon dioxide and water.

The balanced reaction is:

4 CH₃OH + 3 O₂ → 4 CO₂ + 2 H₂O

8 0
3 years ago
Read 2 more answers
Other questions:
  • We wish to coat flat glass (n = 1.50) with a transparent material (n = 1.20) so that reflection of light at wavelength 529 nm is
    6·1 answer
  • Differentiate between earthworm and housefly​
    11·1 answer
  • Speedy Sue, driving at 32.0 m/s, enters a one-lane tunnel. She then observes a slow-moving van 170 m ahead traveling with veloci
    6·1 answer
  • How many discovered planets are there
    15·1 answer
  • How does the jet stream affect the movement of air masses
    12·1 answer
  • If a proton and electron both move through the same displacement in an electric field, is the change in potential energy associa
    5·1 answer
  • Si un movil parte del reposo logrando una aceleracion de 5 metros por segundo al cuadrado durante 8 segundos calcular la velocid
    5·1 answer
  • De las ondas electromagnéticas, se puede afirmar que:
    14·1 answer
  • Really need help! ;(<br> Could you please explain it? :) <br> GIVING 10 POINTS
    5·2 answers
  • A ball rolls from x=3.85m to x=22.1m in 5 seconds. What was its average velocity
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!