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3241004551 [841]
3 years ago
12

A charged particle enters a uniform magnetic field B_vec with a velocity v_vec at right angles to the field.It moves in a circle

with period T.1. If a second particle, with the same electric charge but tentimes as massive, enters the field with the same velocity v_vec, what is its period?A. T/10B. TC. 5TD. 10T
Physics
1 answer:
Finger [1]3 years ago
8 0

Answer:

D. 10 T

Explanation:

When a particle is moving in a magnetic field, the magnetic force provides the centripetal force that keeps the particle in circular motion.

The cyclotron period (the period the particle takes to complete one orbit) can be found to be

T=\frac{2\pi m}{qB}

where

m is the mass of the particle

q is its charge

B is the magnetic field

As we see, the period is directly proportional to the mass of the particle.

In this problem, the second particle is ten times as massive as the first one:

m' = 10 m

while the speed is the same. So, the period of the second particle is

T'=\frac{2\pi m'}{qB}=\frac{2\pi (10m)}{qB}=10 \frac{2\pi m}{qB}=10 T

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Answer:

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Explanation:

From the question ewe are told that

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Generally, the rate of heat transfer is mathematically represented as

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=>         T  =  \sqrt[4]{\frac{P}{e* \sigma } }

where  \sigma is the Boltzmann constant with value  \sigma  = 5.67*10^{-8} \ W\cdot  m^{-2} \cdot  K^{-4}.

substituting value  

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            T  = 168.44 \ K

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Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject
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Answer:

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Explanation:

Given data:

weight of spacecraft is 2000 kg

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time required for the mission is given as t

t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}

where

\mu_{sun} is gravitational parameter of sun =  1.32712 x 10^20 m^3 s^2.t = \frac{2\pi}{\sqrt{ 1.32712 x 10^{20}}} [\frac{1}{2}(149.6 * 10^ 6 +1.43 *10^9 )]^{3/2}

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Calculate delta g for the reaction if the partial pressures of the initial mixture are pcl5 = .0029 atm, pcl3 = .27 atm, and pcl
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Answer: equation for the reaction is given below

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