Answer:
time is 3333.33 min or 55.55 hr
Explanation:
given data
reactor operating = 1 MW
negative reactivity = $5
power = 1 miliwatt
to find out
how long does it take
solution
we know here power coefficient that is
power coefficient =
power coefficient = 1
so time required to reach power is
power = reactivity × time / power coefficient + reactor operating
1 × = -5 t / 1 + 1 ×
5t = -
t = 199999.99 sec
so time is 3333.33 min or 55.55 hr
Answer:
a) L = 3.29 10⁻⁴ H, b)U = 5.33 10⁻² J
Explanation:
a) The inductance is a solenoid this given carrier
L =
The magnetic field inside the solenoid is
B = μ₀
hence the magnetic flux
Ф_B = B. A = μ₀
we substitute in the expression of inductance
L = N² μ₀ A /l
let's find the area of each turn
A = π r²
A = π 0.02²
A = 1.2566 10⁻³ m²
let's calculate
L = 250² 4π 10⁻⁷ 1.2566 10⁻² / 0.3
L = 3.29 10⁻⁴ H
b) The stored energy is
U = ½ L i²
let's calculate
U = ½ 3.29 10⁻⁴ 18²
U = 5.33 10⁻² J