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3 years ago

Write down the role played by four digestive juices in digestion and the

Physics

1 answer:

valentinak56 [21]3 years ago

3 0

Answer:

Digestive juices secreted by various organs such as salivary glands in the mouth, stomach, liver and pancreas help in the process of digestion of food. Saliva secreted by the salivary glands in the mouth aids in the breakdown of starch present in the food to simple sugar

Explanation:

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The water in the plumbing in a house is at a gauge pressure of 300,000 pa. What force does this cause on the top of the tank ins

liraira [26]

Answer:

60 000 N

Explanation:

1 pa = 1 N/m^2

you have 300 000 of these = 300 000 N /m^2

but only an area of .2 m^2

300 000 N / m^2 * .2 m^2 = 60 000 N

3 0

2 years ago

What is 3.75 x 10^-7?

pogonyaev

Answer:

Explanation:

3.75 * 10^-7

=3.75 * 1/10^7

=3.75/10000000

=3/800000000

any base which has it's power negative do it's reciprocal then the power will be positive.

8 0

3 years ago

Describe why an object sinks or floats based on Archimedes Principle.

blondinia [14]

AN OBJECT FLOAT BECAUSE OF ITS LOW CAPACITY AND SINKS BECAUSE OF ITS HIGH CAPACITY

7 0

3 years ago

a particle is moving in a circle of radius R with constant speed.The time period of particle is T=1 second.In a time t=T/6,if th

12345 [234]

at t=T/6, total distance covered= 2*pi*r/6 and displacement= r

difference of them = 2*t
so, 2*pi*r/6- r =2(1/6)=1/3

r=1/(pi-3)=7.062

4 0

3 years ago

Read 2 more answers

The cornea behaves as a thin lens of focal lengthapproximately 1.80 {\rm cm}, although this varies a bit. The material of whichi

Keith_Richards [23]

Answer:

Explanation:

a )

from lens makers formula

$\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})$

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

$\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})$

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens f = 1.8 cm

image distance v = ?

lens formula

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}$

$\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}$

.5555 - .04

= .515

v = 1.94 cm

c )

magnification = v / u

= 1.94 / 25

= .0776

size of image = .0776 x size of object

= .0776 x 10 mm

= .776 mm

It will be a real image and it will be inverted.

5 0

3 years ago