Answer:

Explanation:
It is given that,
Radius of the circular loop, r = 0.7 m
Magnetic field, B = 0.44 T
In 0.14 s the wire is reshaped from a circle into a square, but remains in the same plane.
Area of the circular wire,


For the area of square,
The circumference of wire, 
Side of square, 
Area of square, 
An emf is induced in the loop due to change in its area. The induced emf is given by :



So, the magnitude of the average induced emf is 1.10 volts. Hence, this is the required solution.
Answer:
r is the separation between the two spherical bodies
The electric force between two charge objects is calculated through the Coulomb's law.
F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m.
Answer:
The wire would stick to the magnet????????????????????????
Explanation: