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zhannawk [14.2K]
1 year ago
9

384 of the 403 people on a plane are passengers.

Mathematics
1 answer:
Artist 52 [7]1 year ago
6 0

19/403 of the people on the plane are crew

<h3>How to determine the crew fraction?</h3>

The given parameters are:

Population = 403

Passengers = 384

The number of crew is calculated using:

Crew = 403 - 384

Evaluate

Crew = 19

The fraction of crew is then calculated using:

Fraction = Crew/Population

This gives

Fraction = 19/403

Hence, 19/403 of the people on the plane are crew

Read more about fractions at:

brainly.com/question/11562149

#SPJ1

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What is the area of a circle with a diameter of 12.6 in.?
Zepler [3.9K]

Hey there! I'm happy to help!

To find the area of a circle, you square the radius and then multiply by pi (3.14 in our case).

The radius is half of the diameter.

12.6/2=6.3

We square this.

6.3²=39.69

We multiply by 3.14

39.69×3.14=124.6266

We round to the nearest hundredth, giving us an area of 124.63 in².

Now you can find the area of a circle! Have a wonderful day! :D

5 0
3 years ago
Help please i don’t know how to do it
Norma-Jean [14]

Answer:

Step-by-step explanation:

\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\

From the initial condition,

\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C

So we have that \ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1

4 0
2 years ago
HELP WILL MARK YOU BRAINLIEST!!!
Vlad [161]

Answer:

<PQR=132°

plz mark me brainliest

3 0
3 years ago
Both Andrew and Karleigh recorded the distance they ran in x minutes on treadmills. Andrew A 2-column table with 2 rows. Column
mars1129 [50]

Answer:

ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.

That is, S = D/t

Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have

S1 = D1/t

We can then say he ran a distance

D1 = t × S1

= 3600S1

Similarly, let's say Karleigh ran a distance

D2 = t × S2

= 3600S2

Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.

Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10

D1 = 3600 × 5

= 18000

D2 = 3600 × 10

= 36000

This makes D2 bigger than D1. this is an example i found on the internet.

Step-by-

hope this helps, good luck

7 0
3 years ago
Read 2 more answers
29×5/6 how do you solve it
frutty [35]
Is the whole thing divided by 6 or just the 5?
7 0
3 years ago
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