Answer:
population = 600
heterozygotes = 2pq
The homozygous recessive percentage = 
q = 0.1
Solve for q:
∴ q = 
∴ q = 
∴ q = 0.316
solve for p:
for p + q = 1,
thus p = 1 – q = 1 – 0.316 = 0.684
The heterozygotes = 2pq
2pq = 2 x 0.316 x 0.684 = 0.432
600 x 0.432 = 259.2 = 259
so, the population reaches Hardy Weinberg equilibrium, 259 of indviduals should be heterozygous for this trait.
Hence, the correct answer is 259
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Well I know that many diseases break down in the cell communication and cell cycle is how cells move or their stages
AC can be produced by using a device is called as an alternator. This device is a special type of electrical generator designed to produce alternating current. A loop of wire is rotated inside of a magnetic field, which induces a current along the wire.
Answer:
Cyclin dependent kinase 1 or CDK 1 is a catalytic protein whose action is regulated by cyclin B.
Explanation:
CyclinB-CDK 1 complex is also termed as maturation promoting factor that helps in the entry of the cell into the M phase.The concentration of Cyclin B -CDK1 rises by various process such as dephosphorylation and falls by the degradation of cyclin B.
The cyclinB-CDK 1 is inactivated by phosphorylation of at tyr 15 residue.cyclinB-CDK1 interacts with various proteins such as survivin,which is essential for spindle formation that in turn regulate the cell viability.
Primary succession occurs when there are no remains of the previous ecosystem.
Secondary succession occurs when there are still remains of the ecosystem, so secondary succession kind of has a head start.
