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Black_prince [1.1K]
3 years ago
7

Someone please help me :((

Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0
8x^2-3 = sqrt(16x+9)
[8x^2-3]^2 = [sqrt(16x+9)]^2 ... square both sides
64x^4-48x^2+9 = 16x+9
64x^4-48x^2+9-16x-9 = 0
64x^4-48x^2-16x = 0
16x(4x^3-3x-1) = 0
16x(x-1)(2x+1)^2 = 0
16x=0 or x-1=0 or (2x+1)^2 = 0
x=0 or x=1 or x = -1/2

The possible solutions are x=0 or x=1 or x = -1/2

We need to check all the possible solutions

Checking x=0
8x^2-3 = sqrt(16x+9)
8(0)^2-3 = sqrt(16*0+9)
-3 = 3
The equation is false so x=0 is extraneous (not a real solution)

Checking x=1
8x^2-3 = sqrt(16x+9)
8(1)^2-3 = sqrt(16*1+9)
5 = 5
Equation is true. The value x=1 is a solution

Checking x=-1/2
8x^2-3 = sqrt(16x+9)
8(-1/2)^2-3 = sqrt(16(-1/2)+9)
-1 = 1
The equation is false so x=-1/2 is extraneous (not a real solution)

Therefore, the only answer is choice A) 1
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HELP ASAP BEING TIMED! If Triangle J K L is congruent to Triangle B C A, which statement must be true?
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Answer:

Choice C

Step-by-step explanation:

This is like a matching question. Here's what I mean by this. We know Triangle BCA and Triange JKL are congruent. So, what we have to do is match the side lengths together.

So the first side of BCA matches with JKL, the second side of BCA matches with JKL, the third side of BCA matches with JKL.

So first side:

BC is congruent  to JK

So second side:

CA is congruent  to KL

So third side:

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The third side is one of our answer choices.

That answer choice is C.

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I need help I need help
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Answer:

{ \boxed{ \bf{c}}} \:   \: \frac{3.8}{4}  = s

Step-by-step explanation:

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The answer of the question is D
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