What is the solubility of iron in water at 25 degrees Celsius

In a paragraph, explain what the story of the Gadarene demoniac teaches us about our life in Christ.

GarryVolchara [31]

Answer:

Just like the previously possessed man told people about his new life in Christ, we, too, should share about our new life in Christ.

Explanation:

The story of the demonaic is about a possessed man whose unclean spirits were sent out by Jesus. The spirits were sent into the pigs of the people who raised them to sell for profit (some of which were the Jew's pigs,) and they ran off the cliff and drowned. The owners of these pigs knew that Jesus did it to save the man but still were mad and wanted nothing to do with Jesus. They told Him to leave even though He saved the possessed man who they had previously tried to help. The man wanted to travel with Jesus, but He told the healed man to depart from Him and go to the people and share his story and how Jesus helped Him, and he obeyed. Just like the previously possessed man told people about his new life in Christ, we, too, should share about our new life in Christ.

Hope this helps. Don't hate me if it's wrong but this is what I found.

6 0

2 years ago

What mass of aluminum sulfate is required to precipitate all of the Ba?? out of 45.0 mL of 0.548 M barium nitrate solution? 3 Ba

Verizon [17]

Answer:

2.82 g

Explanation:

Step 1: Write the balanced precipitation reaction

3 Ba(NO₃)₂ (aq) + Al₂(SO₄)₃ (aq) ⇒ 3 BaSO₄(s) + 2 Al(NO₃)₃(aq)

Step 2: Calculate the reacting moles of Ba(NO₃)₂

45.0 mL (0.0450 L) of 0.548 M Ba(NO₃)₂ react.

0.0450 L × 0.548 mol/L = 0.0247 mol

Step 3: Calculate the moles of Al₂(SO₄)₃ that react with 0.0247 moles of Ba(NO₃)₂

The molar ratio of Ba(NO₃)₂ to Al₂(SO₄)₃ is 3:1. The reacting moles of Al₂(SO₄)₃ are 1/3 × 0.0247 mol = 8.23 × 10⁻³ mol

Step 4: Calculate the mass corresponding to 8.23 × 10⁻³ moles of Al₂(SO₄)₃

The molar mass of Al₂(SO₄)₃ is 342.2 g/mol.

8.23 × 10⁻³ mol × 342.2 g/mol = 2.82 g

5 0

3 years ago

Perform each of the following unit conversions using the conversion factors given below: 1 atm = 760 mmHg = 101.325 kPa

Alenkasestr [34]

unit coversation
1.429 atm - 1086mmhg

9361 pa-9.36 KPa - 70.21 mmhg

725 mmhg -0.95 atm- 96.26 kpa

calculation

(a) 1 atm = 760 mmhg
1.429 atm = ?
1.429 x760/1 = 1086.34 mm hg

(B) 1 mmhg = 101.325 kpa
? =9361 KPa
9361 x1 /101.25 =70.21 mmhg

760 mm hg= 101.325 KPa
70.21 mm hg=?

70.21 x101.325/760 = 9.36 Kpa

(C ) 1 atm = 760 mmhg
? = 725
= 725 x1/ 760=0.95 atm

1 atm = 101.325 kpa
0.95 =?

0.95 x101.325/1 = 96.26 KPa

5 0

4 years ago

Read 2 more answers

What you can and what you can’t do to energy?

Yanka [14]

You can't create energy and you can transform it

7 0

3 years ago

Read 2 more answers

2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average

butalik [34]

Answer:

This question is incomplete

Explanation:

This question is incomplete but...

1) You can calculate the molarity of the NaOH for each trial by following the steps below.

The formula for Molarity (M) is

M = number of moles (n) ÷ volume (V)

where the unit of volume must be in Litres or dm³

The unit of molarity is mol/dm³ or mol/L or molar conc (M)

The final answer must have the unit of molarity

If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as

n = mass of NaOH used ÷ molar mass of NaOH

Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol

n = mass of NaOH used ÷ 40

2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2

Answer must be in mol/dm³ or mol/L or M

3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above

3 0

3 years ago