The graphs can be described as
So in case of inverse relationship we will obtain a curve not straight line
Your answer would be:
2RbNO3 + BeF2—> Be(NO3)2 + 2RbF
All elements have an equal amount of atoms on each side.
Answer:
The outside temperature is -45.8°C
Explanation:
When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).
V1 / T1 = V2 / T2
2.95L/298K = 2.25L / T2
(2.95L/298K ) . T2 = 2.25L
T2 = 2.25L . 298K / 2.95L
T2 = 227.2K
T°K - 273 = T°C
227.2K - 273 = -45.8°C
Answer:
55 g
Explanation:
First, we have to look for the solubility of KNO₃ at 60°C, considering that the solubility is the maximum amount of solute that can be dissolved in 100 grams of solvent, that is, the concentration of a saturated solution.
The solubility of KNO₃ at 60°C is 110.0 g of KNO₃ per 100 g of water. The mass of KNO₃ that must be dissolved in 50 g of water to make a saturated solution is:
50 g H₂O × (110.0 g KNO₃/100 g H₂O) = 55 g KNO₃
