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4 years ago

Perform each of the following unit conversions using the conversion factors given below: 1 atm = 760 mmHg = 101.325 kPa

2 answers:

5 0

unit coversation
1.429 atm - 1086mmhg

9361 pa-9.36 KPa - 70.21 mmhg

725 mmhg -0.95 atm- 96.26 kpa

calculation

(a) 1 atm = 760 mmhg
1.429 atm = ?
1.429 x760/1 = 1086.34 mm hg

(B) 1 mmhg = 101.325 kpa
? =9361 KPa
9361 x1 /101.25 =70.21 mmhg

760 mm hg= 101.325 KPa
70.21 mm hg=?

70.21 x101.325/760 = 9.36 Kpa

(C ) 1 atm = 760 mmhg
? = 725
= 725 x1/ 760=0.95 atm

1 atm = 101.325 kpa
0.95 =?

0.95 x101.325/1 = 96.26 KPa

Leto [7]4 years ago

4 0

1atm= 760mmhg= 101.325kPa

1.429atm= 1,086 mmhg

9,361 Pa= 9.361 kPa= 70.21 mmhg

725 mmhg= 954 atm= 96.7 kPa

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A 250. ML sample of 0.3M HCl is partially neutralized by the addition of 100. ML of 0.25M NaOH.Find the concentration of hydroch

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Answer:- 0.143 M

Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:

$HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)$

Let's calculate the initial moles of HCl and the moles of NaOH added to it:

$250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})$

= 0.075 mol HCl

$100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})$

= 0.025 mol NaOH

Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.

Remaining moles of HCl = 0.075 - 0.025 = 0.050

Total volume of the resulting solution = 0.250 L + 0.100 L = 0.350 L

So, the concentration of HCl in the resulting solution = $\frac{0.050mol}{0.350L}$

= 0.143 M

Hence, the concentration of HCl acid in the resulting solution is 0.143 M.

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