Find the Equation of a line that has a slope of 5 and passes through ( 2, 8 ). Detailed answers would be appreciated.

2 answers:

5 0

First you need to fill in the given information into slope intercept form, so y=mx+b. Filling in what you know it would be 8=5(2)+b then just solve it from there like you would a normal equation to find your answer for b. Then plug in the answer you get for b into the original equation. Is this helpful or do you need me to walk you through more steps?

Sophie [7]2 years ago

4 0

Y = 5x+8<slope intercept

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2 years ago

1. The curve y = (x - 1)(x – 5) cuts the x-axis at A and B and the y-axis at C.

saveliy_v [14]

So the first two questions are asking for points of intercept. a is asking where the function crosses the x, in this case it is where y=0. So your x intercept is at x= 1,5. Then to find the y intercept it is where x=0, so just substitute 0 for x. Then you get your y intercept as y=5. Because your coefficient for the quadratic function is positive your function has a minimum since it opens upward. I’m not sure what is means by C coordinate, but your vertex is at (3,-4) and lime of symmetry is at x=3.

X intercepts: (1,0) and (5,0)
Y intercept: (0,5)

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