430m. We use the displacement formula x=v*t+1/2*a*t^2. Set upward to be the positive direction, so v=6m/s, a=-g=-9.8m/s^2 (gravity is pulling the object down), and t=10s. The displacement is -h(it's negative because the ending point is the ground, which is negative relative to the starting point). -h=60-4.9*100, h=430 m.
Given our understanding of the situation, for this vehicle with four wheels is traveling in a <u>linear path</u> through soft dirt, we would expect for<em><u> </u></em><em><u>only two wheels</u></em> to leave tire track impressions.
The vehicle has four wheels, and one might think initially that it makes sense for <u>all four wheels to create tire track impressions</u> on the dirt. This assessment is correct, all <u>four </u><u>tires </u><u>will create impressions</u>, However, <u><em>not all four </em></u><u><em>tires</em></u><u><em> will leave a said </em></u><u><em>impression</em></u>.
This is due to the fact that as the vehicle advances, the tires in the back <em>will erase the </em><em>impressions </em><em>left by the </em><em>front tires</em>. Therefore, <u>only </u><u>two </u><u>tire </u><u>track impressions </u><u>will be left.</u>
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Acceleration of the cabinet= 0956 m/s²
Explanation:
Total force=25+18=43 N
mass of cabinet=45 kg
now F = m a
a= F/m
a=43/45
a=0.956 m/s²
Thus the acceleration of the cabinet=0.956 m/s²