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Elena-2011 [213]
3 years ago
15

An object thrown vertically upward with a speed of 6 m/s from a height of h meters takes 10 seconds to reach the ground. set up

and solve the initial-value problem that governs the motion of the object, and determine h. (use g = 9.8 m/s2 for the acceleration due to gravity.)
Physics
1 answer:
nexus9112 [7]3 years ago
3 0
430m. We use the displacement formula x=v*t+1/2*a*t^2. Set upward to be the positive direction, so v=6m/s, a=-g=-9.8m/s^2 (gravity is pulling the object down), and t=10s. The displacement is -h(it's negative because the ending point is the ground, which is negative relative to the starting point). -h=60-4.9*100, h=430 m. 
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4vir4ik [10]

Answer:

Explanation:

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a )

current I = 14 .0 t

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b )

Voltage across capacitor

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= 7 t² / C

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c ) Let after time t energy stored in capacitor becomes equal the energy stored in capacitance

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= 1/2 L I²

energy stored in capacitor

= 1/2 CV²

After time t

1/2 L I² = 1/2 CV²

L I² =  CV²

L x ( 14 t )² = C x  ( 7 t² / C )²

L x 196 t² = 49 t⁴ / C

t² = CL x 196 / 49

t = 74.8 μ s

After 74.8 μ s energy stored in capacitor exceeds that of inductor.

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3 years ago
Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?​
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8a2-10ab+15b+10 Explaintion:

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PLEASE ANSWER WILL GIVE BRAINLIEST
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Answer:

B. NET force: 2 resultant motion: left

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D. Net Force: 7 Resultant motion: right

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E. Net Force:0 resultant motion: NO MOTION

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F. NET Force: 3 resultant motion: Down

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H. Net force: 3 Resultant motion: left

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L. Net force: 0 resultant motion:No motion

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Answer:

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kolezko [41]

Answer:

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