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Rudiy27
2 years ago
12

what is the pressure on a circular helipad of diameter 100 m on which a helicopter of weight 40,000 N is landing. *

Physics
1 answer:
Luba_88 [7]2 years ago
4 0

Answer:

5.09 Pa

Explanation:

Area of the circle = πr²

The diameter is given, so 100/2 = 50 m is the radius.

π x 50² = 7854 m²

Pressure = force/area

Pressure = 40000/7854

Pressure = 5.09 Pa

Hope this helps!

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Which pair of triangles can be proven congruent by the hl theorem?
hoa [83]

The pairs of triangles that can be proven congruent by the hl theorem is the right angled triangle.

<h3>What is mearnt be the HL theorm?</h3>

The HL theorem is also known as the Hypothenus Leg theorem, it states that "the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent."

Learn more about the postulates of the HL theorem here:

brainly.com/question/25922842

4 0
2 years ago
What is the hang time when the person moves 6 m horizontally during a 1.25 m high jump?
AlekseyPX

Answer:

1 sec

Explanation:

Horizontal distance (x) = 6m

Vertical distance (y) = 1.25m

Hang time is the duration the object is in the air before it reaches maximum height.

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t = √2y/g

g = acceleration due to gravity

t = √(2*1.25)/9.8

t = √2.5/9.8

t = 0.5secs

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= 1 sec

3 0
3 years ago
Briefly describe the three intelligences included in Robert Sternberg’s triarchic theory of human intelligence.
pshichka [43]
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7 0
3 years ago
A packing crate rests on a horizontal surface. It is acted on by three horizontal forces: 600 N to the left, 200 N to the right,
egoroff_w [7]

Answer:

The resultant force would (still) be zero.

Explanation:

Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.

In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.

By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.

When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.

However, recall that before the 600-N force is removed, the friction on the crate is 400 N. The normal force on the crate (which is in the vertical direction) did not change. As a result, one can hence be assured that the maximum friction would be at least 400 N. That's sufficient for balancing the 200-N force to the right. Hence, the resultant force on the crate would still be zero, and the crate won't move.

6 0
3 years ago
A box has a mass of 150kg and the surface area of the bottom of the box is :
charle [14.2K]

Answer:

Pressure = 100 Pascals

Explanation:

pressure =  \frac{force}{area}  \\  =  \frac{150 \times 10}{15}  \\  =  \frac{1500}{15}  \\  = 100 pa

3 0
3 years ago
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