2.6 sec (look it up) for more accurate
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Answer:
- 91499.95 V
Explanation:
Let the mid point is P.
qA = 3.4 pC = 3.4 x 10^-12 C
qB = - 6.10 micro Coulomb = - 6.10 x 10^-6 C
AB = 1.20 m
AP = BP = 0.6 m
Let the potential at P due to the charge at A is VA and the potential at P due to the charge at B is VB.
The potential at P is V
V = VA + VB
V = 0.051 - 91500
V = - 91499.95 V
Answer:
t is appropriate to clarify that units such as time and angles the transformation is not in base ten, for example:
60 s = 1 min
60 min = 1 h
24 h = 1 day
Therefore, for this transformation, you must be more careful
the length transformation is base 10
Explanation:
In many exercises the units used are transformed by equations into other units called derivatives, in general the transformation of derived units is the product of the transformation of the constituent units.
In the example of velocity, the derivative unit is m / s, which is why it works in the same way that you transform length and time if in the equation it is multiplying it is multiplied and if it is dividing it is divided.
It is appropriate to clarify that units such as time and angles the transformation is not in base ten, for example:
60 s = 1 min
60 min = 1 h
24 h = 1 day
Therefore, for this transformation, you must be more careful
the length transformation is base 10
1000 m = 1 km
