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3 years ago

This exists in the space surrounding a charged particle and exerts a force on other charged particles.

Physics

2 answers:

melamori03 [73]3 years ago

7 0

Answer:

Nope,(not expert certified)

Electrical Field is the correct answer.

Explanation:

Zinaida [17]3 years ago

4 0

Gravitational field exists in the space surrounding a charged particle and exerts a force on other charged particles. Gravitational waves are ripples of waves travelling outward from the source. The more massive the orbit of two bodies, the more it emits gravitational wave. And everything around it that is near within the wave experiences a ‘pull’ toward the orbiting bodies.

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Which of the following best explains why mutations cannot cause evolution?

il63 [147K]

A gene mutation is a permanent alteration in the DNA sequence that makes up a gene, such that the sequence differs from what is found in most people. Mutations range in size; they can affect anywhere from a single DNA building block (base pair) to a large segment of a chromosome that includes multiple genes. <span>Most disease-causing gene mutations are uncommon in the general population. However, other genetic changes occur more frequently. Genetic alterations that occur in more than 1 percent of the population are called polymorphisms. They are common enough to be considered a normal variation in the DNA. </span>

4 0

4 years ago

A space vehicle is traveling at 3760 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The

almond37 [142]

Answer:

3688 km/h

Explanation:

Given:-

- The speed of vehicle relative to earth, vs_e = 3760 km/h

- The relative speed of command and motor, v_c/m = 90 km/h

- The mass of command = m

- The mass of motor = 4m

Find:-

What is the speed of the command module relative to Earth just after the separation?

Solution:-

- Consider the space vehicle as a system that detaches itself into two parts ( command and motor ). We will assume that the gravitational pull due to Earth on the space vehicle is negligible. With that assumption we have our system in isolation. We will apply the principle of conservation of linear momentum on the system as follows:

Initial momentum = Final momentum

Pi = Pf

M*vs_e = m*vc_e + 4m*vm_e

Where,

M = m + 4m = 5m

vc_e = Velocity of command relative to earth

vm_e = Velocity of motor relative to earth

- We will develop a relation of velocities of command and motor in the frame of earth as follows:

vm_e = v_c/m + vc_e

- Substituting (vm_e) from Equation 2 into Equation 1, we have:

5m*vs_e = m*vc_e + 4m*(v_c/m + vc_e)

5m*vs_e = 5m*vc_e + 4m*(v_c/m)

- Solve for vc_e:

5m*vs_e - 4m*(v_c/m) = 5m*vc_e

vs_e - 0.8*(v_c/m) = vc_e

- Plug in values and evaluate vc_e:

vc_e = 3760 - 0.8*(90)

vc_e = 3,688 km/h

5 0

4 years ago

Read 2 more answers

What is the magnitude of the electric field at the point (8.70 - 9.10 7.20 ) m if the electric potential is given by V

frez [133]

This question is incomplete, the complete question is;

What is the magnitude of the electric field at the point (8.70i - 9.10j + 7.20k ) m if the electric potential is given by V = 4.30xyz², where V is in volts and x, y and z are in meters.

Answer:

the magnitude of the electric field is 5648.67 N/C

Explanation:

Given the data in the question;

Suppose electric field at this point is;

E = Exi + Eyj + Ezk

Now, electric field is given by;

E = -dV/dr

so,

Ex = -d( 4.30xyz² )/dx = -4.30yz²

Ey = -d( 4.30xyz² )/dy = -4.30xz²

Ez = -d( 4.30xyz² )/dz = -8.60xyz

E = -4.30yz² i - 4.30xz² j - 8.60xyz k

now, at the point (8.70i - 9.10j + 7.20k )

E = (-4.30(-9.10)(7.20)²) i + (-4.30(8.70)(7.20)²) j + (-8.60(8.70)(-9.10)(7.20) k

E = 2028.499 i - 1939.334 j + 4902.206 k

so, Magnitude of electric field will be;

|E| = √( Ex² + Ey² + Ez² )

we substitute

|E| = √( (2028.499)² + (-1939.334)² + (4902.206)² )

|E| = √( 31907448.222993 )

|E| = 5648.67 N/C

Therefore, the magnitude of the electric field is 5648.67 N/C

5 0

3 years ago

Consider the transition from the energy levels n = 3 to n = 6. what is the wavelength associated with this transition, in nm?

Anuta_ua [19.1K]

In quantum chemistry, when the energy of electron changes by moving from orbital to orbital, it emits or absorbs energy in the form of light. When this happens, you can measure its wavelength. Suppose an atom is heated. This excites the electron so it moves up higher to the next orbital. As a result, it would emit light. When its energy lowers and moves one orbital lower, it would absorb light. The equation to determine the wavelength is called the Rydberg formula.

1/wavelength = R(1/n1^2 - 1/n2^2), where
R is an empirical constant called Rydberg's constant equal to 1.9074 × 10^7 m^-1
n1 and n2 are orbitals of the atoms such that n2 is always greater than n1.

Substituting the values:

1/wavelength = 1.9074 × 10^7 (1/3^2 - 1/6^2)
wavelength = 1.09 × 10^-6 m or 1.09 micrometers

3 0

3 years ago

You are riding a broomstick and see a golden ball hovering motionless 30 meters directly in front

Alisiya [41]

You should fly at an angle of $14.0^{\circ}$