Answer:
a) the distances are zero, Both 1st & 2nd condition
c) the torques are equal but of the opposite sign, 2nd condition of equilibrium
Explanation:
The equilibrium conditions are
1 translational
∑ F = 0
2 rotational
∑ τ = Σ (F_i x r_i) = 0
They tell us that external torque is zero.
Therefore we have two various possibilities
a) the distances are zero, in this case we have a pure translation movement
for this situation the two equilibrium relations are fulfilled
b) the forces are zero, there is no movement
It does not make sense to use the equilibrium relations since there are no forces
c) the torques are equal but of the opposite sign, the forces are on the opposite side of the body.
In this case the 2 equilibrium relation is fulfilled, but not the first one that the force has the same direction
B, this would balance to a negative charge
Answer:
v = 69.82 ms^-1
Explanation:
As we know,
R = vi2 sin2Ꝋ / g
vi2 =R g / sin2 Ꝋ where R is range R = 52m, Ꝋ = 3 Degrees
vi2 = 52 x 9.8 / sin 2(3) = 4875.227
v = 69.82 ms^-1
Answer:
-0.18 N
Explanation:
The motion of the piece of rubber is a uniformly accelerated motion, so we can find its acceleration using the suvat equation:
where:
v = 10 m/s is the final speed
u = 20 m/s is the initial speed
a is the acceleration
s = 102 m is the distance covered
Solving for a,
The net force acting on the piece of rubber is the force of friction; according to Newton's second law of motion, the force is equal to the product of mass (m) and acceleration (a):
Here we have
m = 0.125 kg is the mass
Therefore, the force of friction is:
And the negative sign means the direction of the force is opposite to the direction of motion.
