Answer:
1) 16.88 atm
2) 34.47 atm
Explanation:
Data:
Volume=0.700L
Temperature = 300K
Number of moles=0.480 mol
Ideal gas constant=0.082057 L*atm/K·mol
1) The ideal gas law is:
(1)
with P the pressure, T the temperature, n the number of moles, V the volume and R the ideal gas constant , so solvig (1) for P:
2) The vander Walls equation is:
solving for P
The change in heat q for the aluminum cup is 141 J.
<h3>What is Specific heat?</h3>
A substance's heat capacity is the amount of heat needed to increase its overall temperature by one degree. The heat capacity is known as the specific heat capacity or the specific heat if the substance's mass is unity.
change in heat -
The amount of heat Q that is transported to create a temperature shift depends on the substance and phase involved, the mass of the system, and the magnitude of the temperature change. (A) The temperature change and the amount of heat transported are directly inversely related.
The answer's sign dig is determined by a calculation's lowest sign digits.
The solution will need 3 digits because the temperatures are provided with 3 significant digits and the specified heat has 3 significant digits (the mass has 4 significant digits).
31.91 g * 0.903 J/g-C * (26.1 - 21.2 C) = 141 J
to learn more about Specific Heat go to - brainly.com/question/21406849
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Answer:
Explanation:
for the calculation of the electric potential inside a parallel plate capacitor you can use the formula for the electric field inside the capacitor.
where d is the distance between plates and E is the electric field, which is given by:
By replacing you obtain:
where Q is the charge stored by the capacitor and A is the area of the plates.
hence, the answer is Qd/Ae0
A. Tree
B. Shapes
C. Grass
D. Mehndi
<h2>
Answer: 15 s</h2>
Explanation:
This is a situation related to vertical motion with constant acceleration, where the equation that will be usefull is:
(1)
Where:
is the final height of the ball (when it reaches the ground)
is the initial height of the ball (is also zero because is thrown from ground)
is the initial velocity of the ball
is the time the ball is in air (on Earth)
is the acceleration due to gravity on Earth
is the acceleration due to gravity on the Moon
Having this clear, let's solve (1) for the Earth:
(2)
(3)
(4)
(5)
(6) This is the initial velocity
Using this same velocity and equation (4) for the Moon:
(7)
Finally finding 
:
