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Kazeer [188]
3 years ago
15

Ezra is pulling a sled, filled with snow, by pulling on a rope attached to the sled. The rope makes an angle θ with respect to t

he horizontal ground, and the sled is being pulled at a constant speed. If the sled and snow have a total mass of m, the acceleration due to gravity is g, the magnitude of the normal force is FN, and the coefficient of kinetic friction between the sled and the ground is μk, what is the angle θ that the rope makes with the ground in terms of these five quantities? (Use the following as necessary: m, g, FN, and μk.)
Physics
1 answer:
svetoff [14.1K]3 years ago
8 0

Answer:

Explanation:

Given

rope makes an angle of \theta

Mass of sled and snow is m

Normal Force =F_N

applied Force is F

as Force is pulling in nature therefore normal reaction is given by

F_N=mg-F\sin \theta

Also F\cos \theta =f_r

f_r=\mu _k\cdot F_N

f_r=\mu _k\cdot (mg-F\sin \theta )

F\cos \theta =\mu _kF_N-------1

F\sin \theta =mg-F_N---------2

Squaring 1 & 2 and then adding

F^2=(\mu _kF_N)^2+(mg-F_N)^2

F=\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}

Substitute value of F in 1

cos\theta =\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}}

\theta =cos^{-1}(\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}})

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3 0
3 years ago
Read 2 more answers
When the weight of the object increase block what is the force of friction applied? Explanation?
erik [133]

Answer:

There is absolutely No relationship between the weight of an object (which is constant) and the frictional force. If a block is sliding on a surface, that surface will be exerting a force on the block. That force can be resolved into a component parallel to the surface (which we call the frictional component), and a component perpendicular to the surface (called the normal component). For many situations, we find experimentally that the frictional component is approximately proportional to the normal component. The frictional component divided by the normal component is defined to be a quantity called the coefficient of kinetic or sliding friction. The coefficient of kinetic friction obviously depends on the nature of the surfaces involved. The normal component on an object can be decreased if you pull in the direction of the normal component (the weight does not change). However pulling this way on the object not only decreases the normal component, but it also decreases the frictional component since they are proportional. This is why it is easier to slide something if you pull up on it while you push it. If you push down, the normal and frictional components increase so it is harder to slide the object. The weight of an object is the downward force exerted by Earth’s gravity on that object, and it does not change no matter how you push or pull on the object.

8 0
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Answer:

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4 0
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