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3 years ago

How long does it take a car travelling at 60 m.p.h to cover 5 miles?

Physics

2 answers:

bixtya [17]3 years ago

8 0

Answer:

2minutes per mile

Explanation:

Not sure if it helps

k0ka [10]3 years ago

6 0

Answer:

Time = 5 minutes

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How does velocity differ from speed? What changes in motion can result in a change in velocity?

olga55 [171]

-Velocity is the speed of any moving object in a given direction, whilst Speed is the rate of an object's ability to move.
-Velocity can change if the direction or time is changed, the basic equation of velocity is: v = d/t
v - velocity
d - distance
t - time
If one of these factors change, it affects the other.

Hope this answers the question!

4 0

3 years ago

Read 2 more answers

A cylindrically shaped piece of collagen (a substance found in the body in connective tissue) is being stretched by a force that

Marat540 [252]

Answer:

Part(a): The value of the spring constant is $3.11 \times 10^{2}~Kg~s^{-2}$ .

Part(b): The work done by the variable force that stretches the collagen is $1.5 \times 10^{-6}~J$ .

Explanation:

Part(a):

If ' $k$ ' be the force constant and if due the application of a force ' $F$ ' on the collagen ' $\Delta l$ ' be it's increase in length, then from Hook's law

$F = k~\Delta l....................................................................(I)$

Also, Young's modulus of a material is given by

$Y = \dfrac{F/A}{\Delta l/l}...............................................................(II)$

where ' $A$ ' is the area of the material and ' $l$ ' is the length.

Comparing equation ( $I$ ) and ( $II$ ) we can write

$&& Y = \dfrac{l~k}{A}\\&or,& k = \dfrac{Y~A}{l}\\&or,& k = \dfrac{Y~(\pi~r^{2})}{l}$

Here, we have to consider only the circular surface of the collagen as force is applied only perpendicular to this surface.

Substituting the given values in equation ( $III$ ), we have

$k = \dfrac{3.10 \times 10^{6}~N~m^{-2} \times \pi \times (0.00093)^{2}~m^{2}}{.027~m} = 3.11 \times 10^{2}~Kg~s^{-2}$

Part(b):

We know the amount of work done ( $W$ ) on the collagen is stored as a potential energy ( $U$ ) within it. Now, the amount of work done by the variable force that stretches the collagen can be written as

$W = \dfrac{1}{2}k~x^{2} = \dfrac{(\dfrac{F}{k})^{2}k}{2} = \dfrac{F^{2}}{2~k}...................................(IV)$

Substituting all the values, we can write

$W = \dfrac{(3.06 \times 10^{-2})^{2}~N^{2}}{2 \times 3.11 \times 10^{2}~Kg~s^{-2}} = 1.5 \times 10^{-6}~J$

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3 years ago

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Snezhnost [94]

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3 years ago

HELP NEEDED! Determine the mechanical energy of this object: a 1-kg ball rolls on the ground at 2 m/s.

valentina_108 [34]

The mechanical energy of an object is the sum of its potential and kinetic energy.

Because the ball is on the ground, its potential energy is 0.
Its kinetic energy is given by:

K.E = 1/2 mv²
K.E = 1/2 x 1 x 2²
K.E = 2 J

Mechanical energy = 2 + 0
Mechanical energy = 2 J

The answer is B.

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3 years ago

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How much work in joules must be done to stop a 920-kg car traveling at 90 km/h?

tankabanditka [31]

Answer:

Work done, W = −287500 Joules

Explanation:

It is given that,

Mass of the car, m = 920 kg

The car is travelling at a speed of, u = 90 km/h = 25 m/s

We need to find the amount of work must be done to stop this car. The final velocity of the car, v = 0