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dem82 [27]
3 years ago
5

How long does it take a car travelling at 60 m.p.h to cover 5 miles?

Physics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

2minutes per mile

Explanation:

Not sure if it helps

k0ka [10]3 years ago
6 0

Answer:

Time = 5 minutes

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A car rounds a flat curve and experiences a centripetal force directed toward the center of the curve and perpendicular to the d
Usimov [2.4K]
<h2>Answer:</h2>

If a car is rounding a flat curve, it experiences a centripetal force that pulls it towards the center of the circle it is rotating in.

Now,

The centripetal force can be balanced by the centrifugal force caused due to the acceleration of the body at the high speed which counters the centripetal force and in turn <u>prevents the car from slipping down the curve.</u>

So,

If the car doesn't hit the gas then the <em><u>car will fall down from the curve</u></em> as the Centripetal force will exceed the Centrifugal force of the car.

However, if the car doesn't hit the brake then the <em><u>car will maintain it's position on the flat curve</u></em> track as the centrifugal force will counter the effect of centripetal force directed towards the center.

3 0
3 years ago
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To accelerate, an object must *
Sonja [21]
Answer: Not 100% sure but I think it’s C.

Hope this helps! ^^
4 0
3 years ago
Which of these pollutants is transferred from soil to water by organic pesticides and fertilizer runoff from farms?
Sedbober [7]
I would say your answer to this question would be D
4 0
3 years ago
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A certain spring stretches 3 cm when a load of 15 n is suspended from it. how much will the spring stretch if 30 n is suspended
Alik [6]
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
k= \frac{F}{\Delta x}
where F is the force applied, and \Delta x is the stretch of the spring with respect to its equilibrium position. Using the data, we find
k= \frac{15 N}{3.0 cm}=5.0 N/cm

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
\Delta x =  \frac{F}{k}= \frac{30 N}{5.0 N/cm}=6 cm
4 0
3 years ago
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A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m? ii. How long it takes to s
Flura [38]

Answer:

Refer to the attachment for solution (1).

<h3><u>Calculating time taken by it to stop (t) :</u></h3>

By using the second equation of motion,

→ v = u + at

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

→ 0 = 5 + (-5/6)t

→ 0 = 5 - (5/6)t

→ 0 + (5/6)t = 5

→ (5/6)t = 5

→ t = 5 ÷ (5/6)

→ t = 5 × (6/5)

→ t = 6 seconds

→ Time taken to stop = 6 seconds

7 0
3 years ago
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