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3 years ago

How long does it take a car travelling at 60 m.p.h to cover 5 miles?

Physics

2 answers:

bixtya [17]3 years ago

8 0

Answer:

2minutes per mile

Explanation:

Not sure if it helps

k0ka [10]3 years ago

6 0

Answer:

Time = 5 minutes

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An object is dropped from a bridge. A second object is thrown downward 1.48 s later. They both reach the water 48.1 m below at t

pashok25 [27]

To solve this problem we will apply the linear motion kinematic equations. With the data provided we will calculate the time of the first object to fall. Later we will get the time difference between the two. This difference will allow us to find the free fall distance. Through the distance we will find the initial velocity, that is,

$x = v_0 t +\frac{1}{2}at^2$

$48.1 = 0*t + \frac{1}{2} (9.8)t^2$

$t = 3.13s$

The second object is thrown downward at one second later and it meets the first object at the water is

$t' = 3.13 -1.48$

$t' = 1.65s$

The distance of the object will travel due to free fall acceleration is

$x = v_0 t+\frac{1}{2} at^2$

$x = 0*(1.65) +\frac{1}{2}(9.8)(1.65)^2$

$x = 13.34m$

The distance of the object will travel due to its initial velocity is

$v_0 = \frac{d_0}{t}$

$d_0 = v_0 t$

$48.1-13.34 = v_0 (1.65)$

$v_0 = 21.06m/s$

Therefore the initial speed of the second object is 21.06m/s

8 0

4 years ago

Helen adjusts the armature of an electric generator by increasing the number of coils around the iron core. What is Helen most l

Luba_88 [7]

Answer:

Explanation:

Got it right on the edge quiz

8 0

3 years ago

Read 2 more answers

What is the symbol for angle?

zlopas [31]

Answer:

angle is denoted by /_ , see in explanation

4 0

4 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass 2kg. When a certain con

BARSIC [14]

Answer:

The acceleration of the second object is 4 m/s².

Explanation:

Given that,

when the a constant force acts upon an object, the acceleration varies inversely with its mass .

$mass\propto \frac{1}{acceleration}$

We can rewrite the equation as

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

When an a certain constant force acts upon an object with mass 2 kg , the acceleration of the object is 26 m/s².

Here, $m_1$ = 2 kg, $a_1$ = 26 m/s², $m_2$ = 13 kg and $a_2=?$

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

$\frac{2}{13}=\frac{a_2}{26}$

$\Rightarrow \frac{a_2}{26}= \frac{2}{13}$

$\Rightarrow {a_2}= \frac{2}{13}\times 26$

$\Rightarrow a_2=4$ m/s²

The acceleration of the second object is 4 m/s².

3 0

3 years ago

When current is flowing through a car’s rear defroster (Exercise 33), the voltage at each end of the metal strips is different.

Yanka [14]

The voltage released because the charges in the current dropped electric potential energy; this energy loss occured due to the resistance of the metal strips.

Explanation:

Current flows from huge voltage (high potential) to base voltage (low potential).
So the end of the strip wherever the current goes at a higher voltage than the end of the strip where the current leaves.
The voltage released because the charges in the current dropped electric potential energy; this energy loss occured due to the resistance of the metal strips.
The electric potential energy converted into thermal energy, heating the strips.

8 0

4 years ago