<span>The elements of the periodic table are classified into three categories: inert gases, nonmetals and metals. Generally, inert gases do not readily gain nor lose electrons, while nonmetals are more likely to acquire electrons. Metals contain low ionization energies, which refer to the amount of energy required to free or remove an electron. These elements also have low electron affinities, or the attractive forces between an incoming electron and the nucleus of an atom. The lower the ionization energies and electron affinities of an atom are, the greater the tendency to lose electrons.</span>
Answer:
xtotal = 90km
displacement = 18km N
Explanation:
To find the total distance traveled by the car, you first calculate the distance traveled by the car when it travels to north. You use the following formula:
(1)
x: distance
v: speed of the car = 30 m/s
t: time = one half hour
In order to calculate the distance you convert the time from hours to seconds:

Then, you replace the values of t and v in the equation (1):
(2)
Next, you calculate the distance traveled by the car when it travels to south:

You convert the time from minutes to seconds:


Finally, you sum both distances x and x':

The total distance traveled by the car is 90km
The total displacement is the final distance of the car respect to the starting point of the motion. This is calculated by subtracting x' to x:

The total displacement of the car is 18km to the north from its starting point of motion.
The stone will take 2.89 seconds to hit the water.
The time required by the stone to hit the water is calculated by the second equaiton of motion
s=ut+
gt^2
41=0×t+
×9.81×t²
t=2.89 seconds
Feathers sharp ,teeth some of them , wings ,backbones
Answer:
f=171.43Hz
Explanation:
Wave frequency is the number of waves that pass a fixed point in a given amount of time.
The frequency formula is: f=v÷λ, where <em>v</em> is the velocity and <em>λ</em> is the wavelength.
Then replacing with the data of the problem,
f=
f=171.43
f=171.43 Hz (because
, 1 hertz equals 1 wave passing a fixed point in 1 second).