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Marysya12 [62]
3 years ago
11

What type of physical change is it when a liquid turns into a solid and a solid turns into a liquid

Chemistry
1 answer:
goblinko [34]3 years ago
4 0

Answer:

Freezing and Melting (Fusion)

Explanation:

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C₆H₁₂O₆ + 6O₂→6CO₂ + 6H₂O + Energy
NeX [460]

Answer:

C₆H₁₂O₆ + 6O₂→6CO₂ + 6H₂O + Energy=chemical equation for cellular respiration

Explanation:

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7 0
3 years ago
Which would have the highest first ionization energy?
LekaFEV [45]

Answer:

Thus, helium has the largest first ionization energy, while francium has one of the lowest.

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3 years ago
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Write the net ionic equation for the following molecular equation Mg (s) +Snso (aq) Mgso4 (aq) Sn(s) Use the lowest possible coe
Simora [160]

Answer:

Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)

Explanation:

Let's consider the following molecular equation.

Mg(s) + SnSO₄(aq) ⇄ MgSO₄(aq) + Sn(s)

The full ionic equation includes al the ions and the species that do not dissociate in water.

Mg(s) + Sn²⁺(aq) + SO₄²⁻(aq) ⇄ Mg²⁺(aq) + SO₄²⁻(aq) + Sn(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the species that do not dissociate in water.

Mg(s) + Sn²⁺(aq) ⇄ Mg²⁺(aq) + Sn(s)

3 0
3 years ago
Which of the following is not true of a scientific theory?
Furkat [3]

Answer: a,b

Explanation: because a scientific theory is something that been thought of and tested multiple times.

3 0
3 years ago
A standard solution of FeSCN2+ is prepared by combining 9.0 mL of 0.20 M Fe(NO3)3 with 1.0 mL of 0.0020 M KSCN . The standard so
Xelga [282]

Answer : The equilibrium concentration of SCN^- in the trial solution is 4.58\times 10^{-8}M

Explanation :

First we have to calculate the initial moles of Fe^{3+} and SCN^-.

\text{Moles of }Fe^{3+}=\text{Concentration of }Fe^{3+}\times \text{Volume of solution}

\text{Moles of }Fe^{3+}=0.20M\times 9.0mL=1.8mmol

and,

\text{Moles of }SCN^-=\text{Concentration of }SCN^-\times \text{Volume of solution}

\text{Moles of }SCN^-=0.0020M\times 1.0mL=0.0020mmol

The given balanced chemical reaction is,

Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons FeSCN^{2+}(aq)

Since 1 mole of Fe^{3+} reacts with 1 mole of SCN^- to give 1 mole of FeSCN^{2+}

The limiting reagent is, SCN^-

So, the number of moles of FeSCN^{2+} = 0.0020 mmole

Now we have to calculate the concentration of FeSCN^{2+}.

\text{Concentration of }FeSCN^{2+}=\frac{0.0020mmol}{9.0mL+1.0mL}=0.00020M

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution

l = path length

\epsilon = molar absorptivity coefficient

\epsilon and l are same for stock solution and dilute solution. So,

\epsilon l=\frac{A}{C}=\frac{0.480}{0.00020M}=2400M^{-1}

For trial solution:

The equilibrium concentration of SCN^- is,

[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]

[SCN^-]_{initial} = 0.00050 M

Now calculate the [FeSCN^{2+}].

C=\frac{A}{\epsilon l}=\frac{0.220}{2400M^{-1}}=9.17\times 10^{-5}M

Now calculate the concentration of SCN^-.

[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]

[SCN^-]_{eqm}=(0.00050M)-(9.17\times 10^{-5}M)

[SCN^-]_{eqm}=4.58\times 10^{-8}M

Therefore, the equilibrium concentration of SCN^- in the trial solution is 4.58\times 10^{-8}M

5 0
3 years ago
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