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2 years ago

Math each description below with the following microscopic pictures(pls help!!!!!)

Chemistry

1 answer:

Keith_Richards [23]2 years ago

6 0

The microscopic pictures i, iii, iv, v, and vi are associated with the descriptions a, d, a, c, and b, respectively. Picture ii does not match with the given options.

To associate each description with the pictures we need to remember that:

Gas is a state in which atoms or molecules move freely around. The gases tend to expand to occupy all the space of the container.

A solid is a state in which the atoms or molecules are very close to each other and cannot move freely, so they will not tend to occupy all the space as the gases do.

Now, let's evaluate each description.

Picture i

In this image, we can see the movement of diatomic gases (or gaseous compounds) composed of the same element. An example of this can be nitrogen gas (N₂), oxygen gas (O₂), hydrogen gas (H₂), and others.

So, this is related to option a: a gaseous compound.

Picture ii

In this, we can see a mixture of gaseous compounds composed of different elements, denoted by different colors (blue and orange). An example can be the mixture of monoxide carbide (CO) with nitrogen (N₂).

Hence, this is associated with a mixture of two gaseous compounds. There is no option related to this image.

Picture iii

In the image, we can see a mixture of monoatomic and diatomic gases. The diatomic gases are composed of two different elements (blue and orange colors).

Therefore, this is related to option d: a mixture of gaseous elements and gaseous compounds.

Picture iv

This image is similar to picture i, but in this, the gaseous compounds are composed of two different elements.

Hence, this description is related to option a: a gaseous compound.

Picture v

In this, we can see that the atoms are close to each other, which corresponds to a solid-state.

Then, this is related to option c: a solid element.

Picture vi

We can see the presence of a mixture of two gaseous elements (both monoatomics), because of the two different colors.

So, this is related to option b: a mixture of two gaseous elements.

Therefore, the descriptions of the pictures i, iii, iv, v, and vi are related to options a, d, a, c, and b, respectively. Picture ii does not match with the given options.

You can learn more about solids here:

brainly.com/question/11549004?referrer=searchResults

brainly.com/question/14424882?referrer=searchResults

I hope it helps you!

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i am begging anyone to help me with this! (all tutors i've asked said they can't solve it but i need someone to help me out) - i

9966 [12]

First, we need to calculate how much energy we will get from this combustion.

Assuming the combustion is complete, we have the octane reacting with O₂ to form only water and CO₂, so:

$C_8H_{18}+O_2\to CO_2+H_2O$

We need to balance the reaction. Carbon only appear on two parts, so, we can start by it:

$C_8H_{18}+O_2\to8CO_2+H_2O$

Now, we balance the hydrogen:

$C_8H_{18}+O_2\to8CO_2+9H_2O$

And in the end, the oxygen:

$C_8H_{18}+\frac{25}{2}O_2\to8CO_2+9H_2O$

We can multiply all coefficients by 2 to get integer ones:

$2C_8H_{18}+25O_2\to16CO_2+18H_2O$

Now, we need to use the enthalpies of formation to get the enthalpy of reaction of this reaction.

The enthalpy of reaction can be calculated by adding the enthalpies of formation of the products multiplied by their stoichiometric coefficients and substracting the sum of enthalpies of formation of the reactants multiplied by their stoichiometric coefficients.

For the reactants, we have (the enthalpy of formation of pure compounds is zero, which is the case for O₂):

$\begin{gathered} \Delta H\mleft\lbrace reactants\mright\rbrace=2\cdot\Delta H\mleft\lbrace C_8H_{18}\mright\rbrace+25\cdot\Delta H\mleft\lbrace O_2\mright\rbrace \\ \Delta H\lbrace reactants\rbrace=2\cdot(-250.1kJ)+25\cdot0kJ \\ \Delta H\lbrace reactants\rbrace=-500.2kJ+0kJ \\ \Delta H\lbrace reactants\rbrace=-500.2kJ \end{gathered}$

For the products, we have:

$\begin{gathered} \Delta H_{}\mleft\lbrace product\mright\rbrace=16\cdot\Delta H\lbrace CO_2\rbrace+18\cdot\Delta H\lbrace H_2O\rbrace \\ \Delta H_{}\lbrace product\rbrace=16\cdot(-393.5kJ)+18\cdot(-285.5kJ) \\ \Delta H_{}\lbrace product\rbrace=-6296kJ-5139kJ \\ \Delta H_{}\lbrace product\rbrace=-11435kJ \end{gathered}$

Now, we substract the rectants from the produtcs:

$\begin{gathered} \Delta H_r=\Delta H_{}\lbrace product\rbrace-\Delta H\lbrace reactants\rbrace \\ \Delta H_r=-11435kJ-(-500.2kJ) \\ \Delta H_r=-10934.8kJ \end{gathered}$

Now, this enthalpy of reaction is for 2 moles of C₈H₁₈, so for 1 mol of C₈H₁₈ we have half this value:

$\Delta H_c=\frac{1}{2}\Delta H_r=\frac{1}{2}\cdot(-10934.8kJ)=-5467.4kJ$

Now, we have 100 g of C₈H₁₈, and its molar weight is approximately 114.22852 g/mol, so the number of moles in 100 g of C₈H₁₈ is:

$\begin{gathered} M_{C_8H_{18}}=\frac{m_{C_8H_{18}}}{n_{C_8H_{18}}} \\ n_{C_8H_{18}}=\frac{m_{C_8H_{18}}}{M_{C_8H_{18}}}=\frac{100g}{114.22852g/mol}\approx0.875438mol \end{gathered}$

Since we have approximately 0.875438 mol, and 1 mol releases -5467.4kJ when combusted, we have:

$Q=-5467.4kJ/mol\cdot0.875438mol\approx-4786.37kJ$

Now, for the other part, we need to calculate how much heat it is necessary to melt a mass, m.

First, we have to heat the ice to 0 °C, so:

$\begin{gathered} Q_1=m\cdot2.010J/g.\degree C\cdot(0-(-10))\degree C \\ Q_1=m\cdot2.010J/g\cdot10 \\ Q_1=m\cdot20.10J/g \end{gathered}$

Then, we need to melt all this mass, so we use the latent heat now:

$Q_2=n\cdot6.03kJ/mol$

Converting mass to number of moles of water we have:

$\begin{gathered} M=\frac{m}{n} \\ n=\frac{m}{M}=\frac{m}{18.01528g/mol} \end{gathered}$

So:

$Q_2=\frac{m}{18.01528g/mol}_{}\cdot6.03kJ/mol\approx m\cdot0.334716kJ/g$

Adding them, we have a total heat of:

$\begin{gathered} Q_T=m\cdot20.10J/g+m\cdot0.334716kJ/g \\ Q_T=m\cdot0.02010kJ/g+m\cdot0.334716kJ/g \\ Q_T=m\cdot0.354816kJ/g \end{gathered}$

Since we have a heat of 4786.37 kJ form the combustion, we input that to get the mass (the negative sign is removed because it only means that the heat is released from the reaction, but now it is absorbed by the ice):

$\begin{gathered} 4786.37kJ=m\cdot0.354816kJ/g \\ m=\frac{4786.37kJ}{0.354816kJ/g}\approx13489g\approx13.5\operatorname{kg} \end{gathered}$

Since we have a total of 20kg of ice, we can clculate the percent using it:

$P=\frac{13.5\operatorname{kg}}{20\operatorname{kg}}=0.675=67.5\%$

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1 year ago

ASAP: The main difference between the gravitational force and electrical force is that

Dahasolnce [82]

Answer:

Electrical force can pull and push

Explanation:

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3 years ago

Many scientist compare the parts of a cell to the parts of a factory. Do you think this comparison is fair and useful?

Fittoniya [83]

Yes. Parts of a cell work together just like stations in a factory.

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3 years ago

"determine the mass of oxygen" in a 7.9 g sample of al2(so4)3.

jeyben [28]

Answer:

4.43 g of Oxygen

Explanation:

As shown in Chemical Formula, one mole of Aluminium Sulfate [Al₂(SO₄)₃] contains;

2 Moles of Aluminium

3 Moles of Sulfur

12 Moles of Oxygen

Also, the Molar Mass of Aluminium Sulfate is 342.15 g/mol. It means,

342.15 g ( 1 mole) of Al₂(SO₄)₃ contains = 192 g (12 mole) of O

So,

7.9 g of Al₂(SO₄)₃ will contain = X g of O

Solving for X,

X = (7.9 g × 192 g) ÷ 342.15 g

X = 4.43 g of Oxygen

7 0

3 years ago

A weather system moving through the American Midwest produced rain with an average pH of 5.02. By the time the system reached Ne

bulgar [2K]

Answer:

The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.

Explanation:

The acidity of a solution depends on the concentration of H⁺ ions ([H⁺]). We can calculate this concentration from the pH using the following expression.

pH = -log ([H⁺])

American Midwest

pH = -log ([H⁺])

5.02 = -log ([H⁺])

[H⁺] = antilog (-5.02) = 9.55 × 10⁻⁶ M

New England

pH = -log ([H⁺])

4.66 = -log ([H⁺])

[H⁺] = antilog (-4.66) = 2.19 × 10⁻⁵ M

The ratio of concentrations is:

$\frac{2.19 \times 10^{-5} M }{9.55 \times 10^{-6} M} =2.29$

The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.

4 0

3 years ago