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sveticcg [70]
3 years ago
15

Sewage and industrial pollutants dumped into a body of water can reduce the dissolved oxygen concentration and adversely affect

aquatic species. In one study, weekly readings are taken from the same location in a river over a two-month period. The week 3 measurement in the data set is suspected of being an outlier.
True or False: According to the Q test, the value at week 3 can be rejected at the 95% confidence level.
Week Dissolved O2 (ppm)
1 4.9
2 5.1
3 5.6
4 4.3
5 4.7
6 4.9
7 4.5
8 5.1
Chemistry
1 answer:
MArishka [77]3 years ago
7 0

Answer:

FALSE

Since 0.385 < 0.526, the value for week 3 is accepted.

Explanation:

Qexp = (|Xq - Xₙ₋₁|)/w

where Xq is the suspected outlier; Xₙ₋₁ is the next nearest data point; w is the range of data

First, the data are arranged in decreasing order, from highest to lowest:

3. 5.6

2. 5.1

8. 5.1

1. 4.9

6. 4.9

5. 4.7

7. 4.5

4. 4.3

Xq = 5.6; Xₙ₋₁ = 5.1; w = 5.6 - 4.3 = 1.3

Qexp = (|5.6 - 5.1|)/1.3 = 0.385

From tables, at 95% confidence level, for n = 8, Qcrit = 0.526

Since 0.385 < 0.526, the value for week 3 is accepted.

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What is the difference between solution and solute​
lana66690 [7]

A solution is a homogeneous mixture consisting of a solute dissolved into a solvent . The solute is the substance that is being dissolved, while the solvent is the dissolving medium. Solutions can be formed with many different types and forms of solutes and solvents.

8 0
3 years ago
Write a question you have about water
nydimaria [60]

Answer:

How many gallons of water are on earth?

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Explanation:

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4 0
3 years ago
At STP, 32 grams of O2 would occupy the same volume as:
ludmilkaskok [199]

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

<h3>Further explanation</h3>

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

  • 4.0 g of He
  • 8.0 g of CH₄
  • 64 g of H₂
  • 32 g of SO₂

Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

\tt \dfrac{32}{32}=1

  • He

\tt mol=\dfrac{4}{4}=1

  • CH₄

\tt mol=\dfrac{8}{16}=0.5

  • H₂

\tt mol=\dfrac{64}{2}=32

  • SO₂

\tt mol=\dfrac{32}{64}=0.5

<em>So mol of 4 g He = mol of 32 g O₂</em>

4 0
3 years ago
Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s
Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

C_{O_2}=8.55\times 10^3g/L

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = \frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L

Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

8 0
3 years ago
SO2 + H2O = H2SO3 and not H2SO4?
kramer
It's because the Law of Conservation of Mass WILL NOT be followed if, from SO2 and water, sulfuric acid is formed. Making a balanced chemical reaction is not possible, no matter what you do. To obtain or make sulfuric acid, SO2 still needs to be oxidized further to SO3.
6 0
3 years ago
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