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sveticcg [70]
3 years ago
15

Sewage and industrial pollutants dumped into a body of water can reduce the dissolved oxygen concentration and adversely affect

aquatic species. In one study, weekly readings are taken from the same location in a river over a two-month period. The week 3 measurement in the data set is suspected of being an outlier.
True or False: According to the Q test, the value at week 3 can be rejected at the 95% confidence level.
Week Dissolved O2 (ppm)
1 4.9
2 5.1
3 5.6
4 4.3
5 4.7
6 4.9
7 4.5
8 5.1
Chemistry
1 answer:
MArishka [77]3 years ago
7 0

Answer:

FALSE

Since 0.385 < 0.526, the value for week 3 is accepted.

Explanation:

Qexp = (|Xq - Xₙ₋₁|)/w

where Xq is the suspected outlier; Xₙ₋₁ is the next nearest data point; w is the range of data

First, the data are arranged in decreasing order, from highest to lowest:

3. 5.6

2. 5.1

8. 5.1

1. 4.9

6. 4.9

5. 4.7

7. 4.5

4. 4.3

Xq = 5.6; Xₙ₋₁ = 5.1; w = 5.6 - 4.3 = 1.3

Qexp = (|5.6 - 5.1|)/1.3 = 0.385

From tables, at 95% confidence level, for n = 8, Qcrit = 0.526

Since 0.385 < 0.526, the value for week 3 is accepted.

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marta [7]

Answer:

Percent yield = 69.4%

Explanation:

Given data:

Percent yield  = ?

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Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂(SO₄)₃ + 3Cu

Number of moles of Aluminium:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Al with copper.

                 Al           :            Cu

                   2           :              3

                0.07         :              3/2×0.07 =0.105 mol                    

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Mass = Number of moles × molar mass

Mass = 0.105 mol × 63.5 g/mol

Mass = 6.7 g

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Percent yield = Actual yield / theoretical yield × 100

Percent yield = 4.65 g/ 6.7 g × 100

Percent yield = 69.4%

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4 years ago
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8 0
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Svetllana [295]

Answer:

Number of moles = 10.6 mol

Explanation:

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Number of moles = mass/molar mass

Now we will calculate the molar mass of citric acid:

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