Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
Answer:-7x(to the power of 2)-3y+4x-2y(to the 3rd power)-7x( to the third power)
Step-by-step explanation:
Collect like terms
You would add the area of the square with the area of the triangle.
Square: length x width
In your case, it would be 100in²
Triangle: length x height x 1/2 (or length x width divided by 2)
16-10 would be 6 (height) 10-6= 4 (length)
6 x 4 x .5 = 12in²
100in²+12in²=112in²
The area is 112in²
Use Pythagorean Theorem:
c = sr (a^2 + b^2) = sr (3^2 + 5.3^2)
= sr (9 + 28.09) = sr (37.09)
= 6.09 = 6.1
