Answer:
Therefore, the four intervals are
(1) 6 - 6.59
(2) 7 - 7.59
(3) 8 - 8.59
(4) 9 - 9.59
The four frequencies are
(1) 4
(2) 3
(3) 1
(4) 6
Step-by-step explanation:
From the data, we have
Interval Frequency
1st 6 - 6.59 4
2nd 7 - 7.59 3
3rd 8 - 8.59 1
4th 9 - 9.59 6
Therefore, the four intervals are
(1) 6 - 6.59
(2) 7 - 7.59
(3) 8 - 8.59
(4) 9 - 9.59
The four frequencies are
(1) 4
(2) 3
(3) 1
(4) 6
Step-by-step explanation:
The number of way to select 2 employees from 40 is 40C2.
The number of way to select 2 employees from 22 is 22C2.
So the probability of the two employees having single-vision correction is just the number of ways to select the 22 employees (22C2) divided by the total number of ways to select 2 employees (40C2).
22C2 / 40C2 = 77/260
We can use the same technique for the bifocal employees.
18C2 / 40C2 = 51/260
It will take 24 minutes until all of them reach the start at the same time.
I might be wrong but it should be 1
