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Mandarinka [93]
3 years ago
15

Consider these two cases. Case 1: An electron jumps from energy level 5 to energy level 2 in an atom. Case 2: An electron jumps

from energy level 5 to energy level 1 in an atom. For case 1, what happens when an electron jumps from energy level 5 to energy level 2 in an atom? A photon is emitted by the atom. A photon is absorbed by the atom. A proton is absorbed by the atom. A proton is emitted by the atom. Assuming that both cases describe Hydrogen‑like atoms with one electron, for which case is more energy emitted or absorbed? More energy is emitted or absorbed for case 1. It is impossible to tell. The energy is the same for both cases. More energy is emitted or absorbed for case 2.
Chemistry
1 answer:
xenn [34]3 years ago
8 0

Answer:

1.  A photon is emitted by the atom.

2. More energy is emitted or absorbed for case 2

Explanation:

The Bohr's model of the atom was based on quantum mechanics idea. He suggested that electrons move in specific spherical orbits round the nucleus.

The claims of his model emphasized on the premise that electrons only move in permissible orbits or energy levels round the nucleus.

The ground state is the lowest energy state available where n= 1.

The excited state is energy levels of n = 2,3,4 .....

Problem 1

For an electron to return to the ground state from a higher energy level, i.e from  5 to 2 in case 1, energy is emitted in form of photons.

Problem 2

More energy is emitted or absorbed when an electron moves from a higher energy level to a more lower one or jumps from a lower energy level to a more higher one.

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A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t
drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t} (1)

<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>  

(a) We can calculate the energy (ΔU) using equation (1):

\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J  

(b) The work is related to pressure and volume by:

\Delta W = -p \Delta V

<em>where p: pressure and ΔV: change in volume = V final - V initial      </em>

\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J

(c) By the definition of Energy, we can calculate q:

\Delta U = \Delta W + \Delta q

<em>where Δq: is the heat transfer </em>

\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J    

I hope it helps you!  

6 0
4 years ago
Use the diagram to answer each question.
Naya [18.7K]

Answer:

84g Thus, 84g of KNO3 must be dissolve in 100 grams of water to form a saturated solution at 50 oC.

and 136 of KNO3 must be dissolve in 100 grams of water to form a saturated solution at 70 oC.

Explanation:

4 0
3 years ago
Which group has the greatest number of valence electrons?
mylen [45]

Answer:

Noble gases

Explanation:

No need

7 0
3 years ago
Would carbon dioxide or water have a higher boiling point? Explain.
oee [108]

Answer:

Water acutually has a higher boiling point because CO2 will turn into a gas form at a certain temp ( -78 C), so CO2 wouldn't really boil very long.

Hope this helps:)

7 0
4 years ago
Given the reaction:
dezoksy [38]

Answer:

V = 22.34 L

Explanation:

Given data:

Volume of O₂ needed = ?

Temperature and pressure = standard

Number of molecules of water produced = 6.0× 10²³

Solution:

Chemical equation:

2H₂ + O₂       →      2H₂O

Number of moles of water:

1 mole contain 6.022× 10²³ molecules

6.0× 10²³ molecules ×  1 mole  /  6.022× 10²³ molecules

0.99 mole

Now we will compare the moles of oxygen and water.

                  H₂O         :            O₂  

                    2            :              1

               0.996         :          0.996

Volume of oxygen needed:

PV = nRT

V = nRT/P

V = 0.996 mol × 0.0821 atm.L/mol.K ×  273.15 K / 1 atm

V = 22.34 L

3 0
3 years ago
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