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bezimeni [28]
3 years ago
10

For which of the following is heat energy released?

Chemistry
2 answers:
Yuliya22 [10]3 years ago
4 0
I think it is a but i might be rong

harkovskaia [24]3 years ago
4 0
For melting and condensing ,heat energy is released.
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Identify the compound with the highest standard free energy of formation. identify the compound with the highest standard free e
Anestetic [448]
The compound with the highest standard free energy of formation is O3(g)


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The freezing point of water is 0.00°C at 1 atmosphere. How many grams of nickel(II) sulfate (154.8 g/mol), must be dissolved in
VladimirAG [237]

Answer:

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Explanation:

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5 0
3 years ago
The conductance of the electric current through the electrolytic solution increases with
katrin2010 [14]

The conductance of the electric current through the electrolytic solution increases with increase in concentration.

<h3>What is electrolysis?</h3>

The term electrolysis has to do with a situation in which liquids conduct electricity by the movement of ions.

The conductivity of the solution depends on the ions present in the solution. Thus, the conductance of the electric current through the electrolytic solution increases with increase in concentration.

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3 0
2 years ago
A)
Karo-lina-s [1.5K]

A  formula unit of the nitrate salt of Q is Q(NO3)2.

<h3>What is IUPAC nomenclature?</h3>

The IUPAC nomenclature was put together by the international Union of Pure and applied chemistry in order to have a uniform way of naming compounds.

We shall now find the names of the compounds;

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2) Potassium cation and cyanide anion ; Potassium cyanide

3) Calcium cation and hypochlorite anion; Calcium oxochlorate I

Knowing that the  valency of NO3^- is one and that the compound formed between Q and  CO3²- has the formula QCO3 we can conclude that a formula unit of its nitrate salt is Q(NO3)2.

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4 0
2 years ago
How many joules (J) are needed to increase the temperature of 10.0 g of lead (Pb) from 30 ˚C to 50 ˚C? (Cp for Pb = 0.128 J/g˚C)
MA_775_DIABLO [31]

Answer:

Q = 25.6 j

Explanation:

Given data:

Energy needed= ?

Mass of lead = 10.0 g

Initial temperature = 30 °C

Final temperature = 50°C

Cp = 0.128 j/g.°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 50°C - 30°C

ΔT = 20°C

Now we will put the values in formula.

Q = 10 g × 0.128 j/g.°C × 20°C

Q = 25.6 j

7 0
3 years ago
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