Answer:
The answer is: +7
Explanation:
Oxidation state or oxidation number of an element is the hypothetical charge on an element that forms completely ionic bonds. The oxidation number represents the number of electrons lost or gained by that element.
Perchlorate ion is a molecule with a chemical formula: ClO₄⁻
The oxidation state of oxygen in ClO₄⁻ = -2,
the total charge on the ClO₄⁻ molecule = -1,
let the oxidation state of chlorine be x
<u><em>As the sum of oxidation states of all elements in a molecule is equal to the total charge on the molecule.</em></u>
⇒ oxidation state of chlorine + oxidation state of oxygen × 4 = total charge on the molecule
⇒ x + (-2) × 4 = -1
⇒ x + (-8) = -1
⇒ x = -1 + 8 = +7
⇒<u> </u><u>x = +7</u>
<u>Therefore, the oxidation state of chlorine in the perchlorate ion (ClO₄⁻): x = +7</u>
<span>There are few main factors affecting the atomic radii, the outermost electrons and the protons in the nucleus and also the shielding of the internal electrons. I would speculate that the difference in radii is given by the electron clouds since the electrons difference in these two elements is in the d orbital and both has at least 1 electron in the 4s (this 4s electron is the outermost electron in all the transition metals of this period). The atomic radio will be mostly dependent of these 4s electrons than in the d electrons. Besides that, you can see that increasing the atomic number will increase the number of protons in the nucleus decreasing the ratio of the atoms along a period. The Cu is an exception and will accommodate one of the 4s electrons in the p orbital.
</span><span>Regarding the density you can find the density of Cu = 8.96g/cm3 and vanadium = 6.0g/cm3. This also correlates with the idea that if these two atoms have similar volume and one has more mass (more protons; density is the relationship between m/V), then a bigger mass for a similar volume will result in a bigger density.</span>
Definition: Cubic centimeter. A cubiccentimetre (cm3) is equal to thevolume of a cube with side length of 1 centimetre. It was the base unit ofvolume of the CGS system of units, and is a legitimate SI unit. It is equal to a millilitre (ml).
Convert ml to cm cubed - Conversion of Measurement Units
The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL
<h3>Balanced equation </h3>
HCOOH + LiOH —> HCOOLi + H₂O
From the balanced equation above,
The mole ratio of the acid, HCOOH (nA) = 1
The mole ratio of the base, LiOH (nB) = 1
<h3>How to determine the volume of LiOH </h3>
- Molarity of acid, HCOOH (Ma) = 0.4 M
- Volume of acid, HCOOH (Va) = 50 mL
- Molarity of base, LiOH (Mb) = 0.15 M
- Volume of base, LiOH (Vb) =?
MaVa / MbVb = nA / nB
(0.4 × 50) / (0.15 × Vb) = 1
20 / (0.15 × Vb) = 1
Cross multiply
0.15 × Vb = 20
Divide both side by 0.15
Vb = 20 / 0.15
Vb = 133.3 mL
Thus, the volume of the LiOH solution needed is 133.3 mL
Learn more about titration:
brainly.com/question/14356286
This is an application of Boyle's law:
P₁V₁ = P₂V₂. we don't have to convert volume and pressure to standard forms. we can even use the pressure with mmHg
1 atm = 760 mmHg
V₂ = P₁V₁ / P₂ = 745 x 500 / 760 = 490 ml
Note that here we assume constant temperature
