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Shkiper50 [21]
4 years ago
15

What motional changes produce an acceleration

Physics
1 answer:
densk [106]4 years ago
6 0
<span>Adolescence is the period of development that begins at puberty and ends at emerging adulthood; the typical age range is from 12 to 18 years, and this stage of development has some predictable physical milestones.</span>
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Definition of fluoresence
denis23 [38]

Answer:

the property of absorbing light of short wavelength and emitting light of longer wavelength.

Explanation:

YW

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3 years ago
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A 6.7kg object moves with a velocity of 8m/s. What's its kinetic energy?
Snezhnost [94]

Given parameters:

Mass of object = 6.7kg

Velocity  = 8m/s

Unknown parameter:

Kinetic energy  = ?

Energy is defined as the ability to do work. There are two forms of energy;

Kinetic and potential energy.

Kinetic energy is the energy due to the motion of a body. Whereas, potential energy is the energy due to the position of a body usually at rest.

Kinetic energy is mathematically expressed as;

             Kinetic energy  = \frac{1}{2} m v^{2}

where m is the mass of the body

           v is the velocity of the body

Since we have been given both mass and velocity, input the parameter to solve for the unknown;

            Kinetic energy  = \frac{1}{2} x 6.7 x 8²   = 214.4‬J

So the kinetic energy of the body is  214.4‬J

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3 years ago
The part of the Electromagnetic (Light) Spectrum used to see through the dust
dimaraw [331]

Answer:

A or C

Explanation:

4 0
3 years ago
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A truck with a mass of 1370 kg and moving with a speed of 12.0 m/s rear-ends a 593 kg car stopped at an intersection. The collis
Elza [17]

Answer:

speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

Explanation:

Given:

mass of truck M = 1370 kg

speed of truck = 12.0 m/s

mass of car m = 593 kg

collision is elastic therefore,

Applying law of momentum conservation we have

momentum before collision = momentum after collision

1370×12 + 0( initially car is at rest) = 1370×v1+ 593×v2               ....(i)

Also for a collision to be elastic,

velocity of approach = velocity of separation

12 -0 = v2-v1                  ....(ii)

using (i) and (ii) we have

So speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

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HEY CAN ANYONE HELP ME OUT IN DIS RQ!!!!!!
shusha [124]

Answer:

40 laps

Explanation:

400/10=40

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